FPGA实现基于时间内插法的TDC测量的具体实现 verilog
时间: 2023-12-23 18:05:40 浏览: 119
verilog-FPGA实例
以下是基于时间内插法的TDC测量在Verilog中的一个简单实现示例:
```verilog
module tdc (
input clk, //输入时钟信号
input rst, //复位信号
input start, //启动信号
input stop, //停止信号
input in_signal, //待测时间信号
output reg [15:0] out_signal //输出时间差值
);
reg [15:0] cnt1;
reg [15:0] cnt2;
reg [15:0] cnt_diff1;
reg [15:0] cnt_diff2;
reg [15:0] out_diff;
reg [1:0] state;
//时钟计数器
always @(posedge clk or posedge rst) begin
if (rst) begin
cnt1 <= 16'h0;
cnt2 <= 16'h0;
state <= 2'h0;
end else begin
case (state)
2'h0: cnt1 <= cnt1 + 1;
2'h1: cnt2 <= cnt2 + 1;
2'h2: cnt1 <= cnt1 + 1;
2'h3: cnt2 <= cnt2 + 1;
endcase
end
end
//比较器
always @(posedge clk or posedge rst) begin
if (rst) begin
cnt_diff1 <= 16'h0;
cnt_diff2 <= 16'h0;
end else begin
case (state)
2'h0: if (in_signal) begin cnt_diff1 <= cnt1; state <= 2'h1; end
2'h1: if (in_signal == 0) begin cnt_diff2 <= cnt2; state <= 2'h2; end
2'h2: if (stop) begin state <= 2'h3; end
endcase
end
end
//内插计算
always @(posedge clk or posedge rst) begin
if (rst) begin
out_diff <= 16'h0;
end else begin
case (state)
2'h3: begin
out_diff <= cnt_diff1 + (cnt_diff2 - cnt_diff1) * (in_signal / 2) / ((in_signal / 2) + (1'b1 - in_signal) / 2);
end
endcase
end
end
//输出
always @(posedge clk or posedge rst) begin
if (rst) begin
out_signal <= 16'h0;
end else begin
case (state)
2'h3: begin
out_signal <= out_diff;
end
endcase
end
end
//启动/停止控制
always @(posedge clk or posedge rst) begin
if (rst) begin
state <= 2'h0;
end else begin
case (state)
2'h0: if (start) begin state <= 2'h1; end
2'h1: if (stop) begin state <= 2'h2; end
endcase
end
end
endmodule
```
在这个Verilog模块中,我们使用了计数器、比较器和内插计算电路来实现基于时间内插法的TDC测量。具体实现中,我们使用了四个状态来控制计数器、比较器和内插计算电路的工作,以实现完整的测量流程。
需要注意的是,这只是一个简单的示例实现,实际应用中需要根据具体需求进行优化和改进。
阅读全文