用python写 The shaded part of the maze is the impassable location. Each position in the maze can explore the feasible path in 8 directions. Assuming that the exit position is at the bottom right corner (6, 8) and the entrance is at the top left corner (1, 1), it is required to design an algorithm to find a path from the entrance to the exit. Maze Problem • Input: The data of Maze,ends with 0 0 • Output: Yes or No. If there is a path from the entrance to the exit, output "Yes". Otherwise, output “No”. 8 10 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 0 1 1 1 1 1 1 0 1 0 1 0 1 0 1 1 0 1 0 0 1 1 1 1 1 1 0 1 1 1 0 0 1 1 1 1 1 0 0 1 1 0 0 0 1 1 0 1 1 0 0 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 6 8 Yes
时间: 2024-01-02 09:03:04 浏览: 27
以下是使用深度优先搜索算法(DFS)来解决迷宫问题的Python代码:
```python
# 读入迷宫数据
maze = []
while True:
row = list(map(int, input().split()))
if row == [0, 0]:
break
maze.append(row)
# 设置起点和终点
start = (1, 1)
end = (6, 8)
# 定义8个方向
directions = [(0, 1), (0, -1), (1, 0), (-1, 0), (1, 1), (-1, -1), (1, -1), (-1, 1)]
# 定义DFS函数
def dfs(current_pos):
if current_pos == end:
# 如果到达终点,返回True
return True
for d in directions:
next_pos = (current_pos[0] + d[0], current_pos[1] + d[1])
if next_pos[0] < 1 or next_pos[0] > len(maze) or next_pos[1] < 1 or next_pos[1] > len(maze[0]):
continue
if maze[next_pos[0]-1][next_pos[1]-1] == 0 or next_pos in visited:
continue
visited.add(next_pos)
if dfs(next_pos):
return True
return False
# 初始化visited集合,并调用DFS函数
visited = set()
visited.add(start)
if dfs(start):
print("Yes")
else:
print("No")
```
这个程序从标准输入中读取迷宫数据,并使用DFS算法来查找从起点到终点的路径。程序先定义了8个方向,然后使用递归函数来实现DFS算法。对于每个当前位置,程序依次尝试向8个方向移动,如果移动到的下一个位置是迷宫中的有效位置且没有被访问过,则递归地调用DFS函数继续搜索下一个位置。如果搜索到终点,则返回True;如果搜索完所有可能的路径都没有找到终点,则返回False。最后,如果DFS函数返回True,则输出"Yes",否则输出"No"。