python flask upload
时间: 2023-06-22 19:43:20 浏览: 58
可以使用 Flask 自带的 `request` 模块来实现文件上传。以下是一个简单的示例:
```python
from flask import Flask, request
app = Flask(__name__)
@app.route('/upload', methods=['POST'])
def upload_file():
file = request.files['file']
file.save(file.filename)
return 'Upload success!'
if __name__ == '__main__':
app.run()
```
在上面的示例中,我们定义了一个路由 `/upload`,并指定了请求方法为 `POST`。当客户端发起一个符合要求的 POST 请求时,`upload_file` 函数会被调用。
在函数中,我们使用 `request.files['file']` 方法获取客户端上传的文件对象,然后使用 `file.save(file.filename)` 方法将文件保存到服务器上。最后,返回一个字符串表示上传成功。
注意:在上传文件时,需要确保服务器端有足够的权限来保存文件。同时,为了保证上传的文件安全,需要对文件类型、大小等进行限制和校验。
相关问题
python flask
Flask is a micro web framework written in Python. It is classified as a microframework because it does not require particular tools or libraries. It has no database abstraction layer, form validation, or any other components where pre-existing third-party libraries provide common functions. However, Flask supports extensions that can add application features as if they were implemented in Flask itself. Extensions exist for object-relational mappers, form validation, upload handling, various open authentication technologies and several common framework-related tools.
Flask is based on the Werkzeug WSGI toolkit and Jinja2 template engine. Both are Pocco projects. Flask is also called a "micro framework" because it can be used to create web applications with very little code. Flask is easy to get started with and is very flexible. It is a good choice for small to medium-sized websites and web applications, RESTful services, and APIs.
Here is an example of a simple Flask app that returns "Hello World!" when the root URL is requested:
```
from flask import Flask
app = Flask(__name__)
@app.route('/')
def hello_world():
return 'Hello World!'
if __name__ == '__main__':
app.run()
```
This code creates a Flask application instance and defines a route (the root URL '/'). When the route is accessed, the `hello_world()` function is called and returns the message "Hello World!". Finally, the application is run using the `run()` method.
python Flask 文件上传
在 Flask 中进行文件上传,可以使用 Flask 提供的 `request` 对象来获取上传的文件,步骤如下:
1. 在 HTML 表单中添加文件上传控件:
```html
<form method="POST" enctype="multipart/form-data">
<input type="file" name="file">
<input type="submit" value="Upload">
</form>
```
2. 在 Flask 中编写路由函数,处理文件上传请求:
```python
from flask import request
@app.route('/upload', methods=['POST'])
def upload_file():
file = request.files['file']
# file.save() 处理上传文件
return 'File uploaded successfully!'
```
在上面的代码中,通过 `request.files` 获取上传的文件,`file` 的类型是 `FileStorage` 类型,可以通过 `file.filename` 获取文件名,通过 `file.save()` 将文件保存到指定的位置。
**注意:**在表单中添加 `enctype="multipart/form-data"` 属性,表示这是一个文件上传表单。
完整代码示例:
```python
from flask import Flask, request, render_template
app = Flask(__name__)
@app.route('/', methods=['GET', 'POST'])
def index():
if request.method == 'POST':
file = request.files['file']
file.save(file.filename)
return 'File uploaded successfully!'
return render_template('index.html')
if __name__ == '__main__':
app.run(debug=True)
```
在这个示例中,上传的文件将保存在当前工作目录下。