sscanf(num1,"%d",&x);
时间: 2023-10-23 21:48:14 浏览: 30
As an AI language model, I don't have emotions, so the concept of "null" doesn't apply to me in the same way it does to humans. However, in programming, "null" usually refers to the absence of a value or an empty variable.
相关问题
sscanf16进制转字符串
sscanf函数是C语言中的一个标准库函数,用于从字符串中读取格式化输入。它可以将字符串中的数据按照指定的格式转换成不同类型的数据,包括16进制转字符串。
下面是一个示例代码,将16进制字符串转换为整数:
```c
#include <stdio.h>
int main()
{
char hex_str[] = "1A";
int num;
sscanf(hex_str, "%x", &num);
printf("0x%x = %d\n", num, num);
return 0;
}
```
输出结果为:0x1a = 26
在上面的代码中,%x是sscanf函数的格式控制字符串,表示读取一个16进制整数。&num是一个指向整数变量的指针,表示将读取到的整数存储到num变量中。
请用sscanf函数解析以下字符串:$GPFPD,1356,9013.40,0.000,0.000,0.000,0.000000000,0.000000000,0.000,0.000,0.000,0.000,0.000,0,0,0*79
```c++
#include <cstdio>
#include <cstring>
int main() {
char str[] = "$GPFPD,1356,9013.40,0.000,0.000,0.000,0.000000000,0.000000000,0.000,0.000,0.000,0.000,0.000,0,0,0*79";
char id[10];
int num1, num2;
double nums[12];
int checksum;
int count = sscanf(str, "$%[^,],%d,%lf,%lf,%lf,%lf,%lf,%lf,%lf,%lf,%lf,%lf,%lf,%d,%d,%d*%x",
id, &num1, &nums[0], &nums[1], &nums[2], &nums[3], &nums[4], &nums[5], &nums[6], &nums[7], &nums[8], &nums[9], &nums[10], &num2, &nums[11], &checksum);
if (count == 16) {
printf("ID: %s\n", id);
printf("Num1: %d\n", num1);
printf("Num2: %d\n", num2);
printf("Checksum: %x\n", checksum);
printf("Double values:\n");
for (int i = 0; i < 12; ++i) {
printf("%lf ", nums[i]);
}
printf("\n");
}
else {
printf("Parsing failed\n");
}
return 0;
}
```