已知某学校有n名教师，学校有m名学生，学校搞学生民意调查，每一位学生为每一位老师都打分，学生所打的所有的分数都集中到一个数组中。数据存放规律是，前m个数据是对1号老师的打分，接下来m个数据是对2号老师的打分，以此类推。请设计一个多线程的算法，计算出每一位老师的总打分。java代码

以下是一个可能的多线程算法，使用线程池来管理线程：

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class TeacherRating {

    private int[] ratings;
    private int numTeachers;
    private int numStudents;

    public TeacherRating(int[] ratings, int numTeachers, int numStudents) {
        this.ratings = ratings;
        this.numTeachers = numTeachers;
        this.numStudents = numStudents;
    }

    public int[] calculateTotalRatings() {
        ExecutorService executor = Executors.newFixedThreadPool(numTeachers);

        int[] totalRatings = new int[numTeachers];

        for (int i = 0; i < numTeachers; i++) {
            final int teacherIndex = i;
            executor.execute(new Runnable() {
                @Override
                public void run() {
                    int total = 0;
                    for (int j = teacherIndex * numStudents; j < (teacherIndex + 1) * numStudents; j++) {
                        total += ratings[j];
                    }
                    totalRatings[teacherIndex] = total;
                }
            });
        }

        executor.shutdown();
        while (!executor.isTerminated()) {}

        return totalRatings;
    }

    public static void main(String[] args) {
        int[] ratings = {3, 4, 5, 2, 1, 3, 2, 5, 4, 1, 3, 2, 4, 5, 1, 2};
        int numTeachers = 4;
        int numStudents = ratings.length / numTeachers;

        TeacherRating teacherRating = new TeacherRating(ratings, numTeachers, numStudents);
        int[] totalRatings = teacherRating.calculateTotalRatings();

        for (int i = 0; i < numTeachers; i++) {
            System.out.println("Teacher " + (i + 1) + " total rating: " + totalRatings[i]);
        }
    }
}

算法将每个老师的计算任务分配给一个线程来完成。使用线程池可以方便地管理线程。在主线程中等待所有线程完成后，算法返回每个老师的总打分。