Find the maximum value among 5 numbers. Hint: ① Define i, max, a[5] as int type, and initialize max=a[0]. ② Input an 5 integer array using scanf() function by loop. ③ Compare max with 5 elements in sequence, and if it is less than one of them, update max. ③ Print max. For example Input: Please enter 5 numbers: 10 6 15 4 8 Output: The maximum value is 15.
时间: 2024-03-08 10:51:11 浏览: 28
Sure, here is the code in C language to find the maximum value among 5 numbers:
```c
#include <stdio.h>
int main() {
int i, max, a[5];
// input 5 numbers
printf("Please enter 5 numbers: ");
for(i=0; i<5; i++) {
scanf("%d", &a[i]);
}
// find the maximum value
max = a[0];
for(i=1; i<5; i++) {
if(a[i] > max) {
max = a[i];
}
}
// output the result
printf("The maximum value is %d.\n", max);
return 0;
}
```
You can copy and paste this code to a C file, and then compile and run it to see the result. Let me know if you have any other questions.
相关问题
error: Pulling is not possible because you have unmerged files. hint: Fix them up in the work tree, and then use 'git add/rm <file>' hint: as appropriate to mark resolution and make a commit. fatal: Exiting because of an unresolved conflict.
这个错误表示你在工作树中有未解决的冲突。在继续拉取之前,你需要解决这些冲突。
以下是解决冲突的一般步骤:
1. 首先,运行以下命令来查看有冲突的文件:
```
git status
```
这将列出所有存在冲突的文件。
2. 打开每个有冲突的文件,并查找带有冲突标记的部分。冲突标记通常以 `<<<<<<<`,`=======` 和 `>>>>>>>` 开始和结束。
例如:
```
<<<<<<< HEAD
这是当前分支的修改
=======
这是要合并分支的修改
>>>>>>> branch-name
```
你需要在这些标记之间进行编辑,以解决冲突。
3. 编辑文件,根据你的需求选择保留哪些修改或者如何合并它们。删除冲突标记并对文件进行适当的修改。
4. 保存文件后,使用以下命令将修改标记为已解决冲突:
```
git add <冲突文件>
```
如果你想跳过某个文件的解决冲突,可以使用以下命令将其标记为已解决:
```
git rm <冲突文件>
```
5. 当你解决完所有冲突并将修改标记为已解决后,使用以下命令进行提交:
```
git commit -m "解决冲突并合并远程分支的最新代码"
```
这将创建一个新的提交,包含了你解决冲突后的代码。
完成提交后,你可以继续你的操作,如拉取远程分支的最新代码或者进行其他操作。
Write a program to get the positions where elements of a and b match. Hint:Use where function: Sample data : a = [1.2.3.2.3.4.3.4.5.61 b= [7,2,10,2,7,4,9,4,9,81 Sample output : [1 3 5 7]
Here is a Python program to get the positions where elements of a and b match:
```python
import numpy as np
a = np.array([1,2,3,2,3,4,3,4,5,6])
b = np.array([7,2,10,2,7,4,9,4,9,8])
match_indices = np.where(a == b)[0]
print(match_indices)
```
Output:
```
[1 3 5 7]
```
Explanation:
1. We first import the numpy library.
2. We define the arrays `a` and `b` using the `numpy.array` function.
3. We use the `numpy.where` function to get the indices where the elements of `a` and `b` match. The output of `where` is a tuple containing an array of row indices and an array of column indices. Since we are dealing with 1-D arrays, we only need the row indices (which are at index 0 of the tuple). We access this array using the `[0]` index.
4. We print the resulting match_indices array.
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