BEGIN FOR i IN 1..10 LOOP INSERT INTO CUSTOMER (CustomerID, Name, Address, PhoneNumber, Email, LoyaltyStatus) VALUES (i, 'Customer ' || i, 'Address ' || i, '123456789', 'customer' || I || '@example.com', 'Bronze'); END LOOP; COMMIT; END; 然后报错 FOR i IN 1..10 LOOP * ERROR at line 2: ORA-06550: line 2, column 5: PLS-00103: Encountered the symbol "FOR" when expecting one of the following: := . ( @ % ; The symbol "(" was substituted for "FOR" to continue. ORA-06550: line 2, column 20: PLS-00103: Encountered the symbol "LOOP" when expecting one of the following: , * & - + / at mod remainder rem when while => <an exponent (**)> by index sequence || multiset

这个错误提示表明你的 SQL 语法有误，可能是因为你在 SQL*Plus 或 SQL Developer 中执行了 PL/SQL 语句而不是 SQL 语句。正确的 SQL 语句应该是这样的：

BEGIN
  FOR i IN 1..10 LOOP
    INSERT INTO CUSTOMER (CustomerID, Name, Address, PhoneNumber, Email, LoyaltyStatus)
    VALUES (i, 'Customer ' || i, 'Address ' || i, '123456789', 'customer' || i || '@example.com', 'Bronze');
  END LOOP;
  COMMIT;
END;

这是一个简单的 PL/SQL 块，用于向 CUSTOMER 表中插入 10 行数据。请确保你在执行这个语句的时候是在 PL/SQL 环境中，而不是在 SQL 环境中。

相关问题

BEGIN FOR i IN 1..10 LOOP INSERT INTO CUSTOMER (CustomerID, Name, Address, PhoneNumber, Email, LoyaltyStatus) VALUES (i, 'Customer ' || i, 'Address ' || i, '123456789', 'customer' || I || '@example.com', 'Bronze'); END LOOP; COMMIT; END;oracle语句里这个对吗

这是一个有效的 Oracle PL/SQL 语句，用于向名为 CUSTOMER 的表中插入 10 行数据。在这个例子中，使用 FOR 循环来插入多行数据，每一行都包含了 CustomerID、Name、Address、PhoneNumber、Email 和 LoyaltyStatus 这些字段的值。最后，使用 COMMIT 语句将所有更改保存到数据库中。

Update the second customer’s email address with this new email address: you@dzi.com， CREATE TABLE CUSTOMER ( CustomerID NUMBER(10) PRIMARY KEY, FirstName VARCHAR2(50), LastName VARCHAR2(50), Email VARCHAR2(100), PhoneNumber VARCHAR2(20) );

To update the second customer's email address with the new email address "you@dzi.com", you can use the following SQL query:

UPDATE CUSTOMER
SET Email = 'you@dzi.com'
WHERE CustomerID = 2;

This assumes that the second customer has a CustomerID of 2 in the CUSTOMER table. If the ID is different, you will need to adjust the query accordingly.

Also, this assumes that the table already exists. If not, you can use the following SQL query to create the CUSTOMER table with the specified columns:

CREATE TABLE CUSTOMER (
  CustomerID NUMBER(10) PRIMARY KEY,
  FirstName VARCHAR2(50),
  LastName VARCHAR2(50),
  Email VARCHAR2(100),
  PhoneNumber VARCHAR2(20)
);

This creates a table named CUSTOMER with columns for CustomerID, FirstName, LastName, Email, and PhoneNumber. The CustomerID column is specified as the primary key.