android 实现代码
时间: 2023-12-19 19:07:59 浏览: 25
这里给出一个简单的 Android 实现代码示例,假设已知两个点为 (x1, y1) 和 (x2, y2),矩形的左上角坐标为 (left, top),右下角坐标为 (right, bottom):
```
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// 已知两点和矩形边框
int x1 = 100;
int y1 = 200;
int x2 = 300;
int y2 = 400;
int left = 150;
int top = 250;
int right = 350;
int bottom = 450;
// 计算矩形的四条边的方程
int a1 = left;
int b1 = top;
int c1 = right;
int d1 = top;
int a2 = right;
int b2 = top;
int c2 = right;
int d2 = bottom;
int a3 = right;
int b3 = bottom;
int c3 = left;
int d3 = bottom;
int a4 = left;
int b4 = bottom;
int c4 = left;
int d4 = top;
// 计算两点之间的直线方程
float k = (float) (y2 - y1) / (x2 - x1);
float b = y1 - k * x1;
// 计算两点直线与矩形四条边的交点
float[] points = new float[8];
points[0] = (b1 - b) / k;
points[1] = b1;
points[2] = c1;
points[3] = k * c1 + b;
points[4] = (d2 - b) / k;
points[5] = d2;
points[6] = a3;
points[7] = k * a3 + b;
// 判断交点是否在矩形内部
List<Float> intersectPoints = new ArrayList<>();
for (int i = 0; i < points.length; i += 2) {
float x = points[i];
float y = points[i + 1];
if (x >= left && x <= right && y >= top && y <= bottom) {
intersectPoints.add(x);
intersectPoints.add(y);
}
}
// 选择距离最近的交点
float minDistance = Float.MAX_VALUE;
float intersectX = 0;
float intersectY = 0;
for (int i = 0; i < intersectPoints.size(); i += 2) {
float x = intersectPoints.get(i);
float y = intersectPoints.get(i + 1);
float distance = (x - x1) * (x - x1) + (y - y1) * (y - y1);
if (distance < minDistance) {
minDistance = distance;
intersectX = x;
intersectY = y;
}
}
// 输出结果
Log.d("MainActivity", "相交点坐标:(" + intersectX + ", " + intersectY + ")");
}
}
```
这段代码先计算了矩形的四条边的方程,然后计算两点之间的直线方程,并分别求出该直线与矩形四条边的交点。接着,判断交点是否在矩形内部,并将符合条件的交点存入一个列表中。最后,从列表中选择距离最近的点作为相交点,并输出结果。