c语言编程计算两度分秒的加减

可以使用以下代码计算两个角度的加减：

#include <stdio.h>
#include <math.h>

// 将角度转化为度分秒格式
void convertToDMS(double angle, int *degrees, int *minutes, double *seconds) {
    *degrees = (int)angle;
    double decimal = angle - *degrees;
    *minutes = (int)(decimal * 60);
    *seconds = (decimal - *minutes / 60.0) * 3600;
}

// 将度分秒格式转化为角度
double convertToAngle(int degrees, int minutes, double seconds) {
    return degrees + minutes / 60.0 + seconds / 3600.0;
}

int main() {
    double angle1, angle2;
    int degrees1, degrees2, minutes1, minutes2;
    double seconds1, seconds2;

    printf("Enter the first angle in degrees, minutes, and seconds:\n");
    scanf("%d %d %lf", &degrees1, &minutes1, &seconds1);
    angle1 = convertToAngle(degrees1, minutes1, seconds1);

    printf("Enter the second angle in degrees, minutes, and seconds:\n");
    scanf("%d %d %lf", &degrees2, &minutes2, &seconds2);
    angle2 = convertToAngle(degrees2, minutes2, seconds2);

    // 计算角度和
    double sum = angle1 + angle2;
    printf("The sum of the angles is: %f degrees\n", sum);

    // 计算角度差
    double diff = fabs(angle1 - angle2);
    printf("The difference between the angles is: %f degrees\n", diff);

    return 0;
}

该程序首先将输入的两个角度转换为度分秒格式，然后将它们转换为角度进行计算。最终输出角度和和角度差。