求一维整型数组中的最小元素。要求:主函数定义数组y[50],y[j]=600*sin(j*0.16) (j=0,1,2…49),调用自定义函数qmin求出最小元素,最后在主函数中输出结果。要求必须使用
时间: 2023-04-17 18:00:33 浏览: 86
C语言编写。
代码如下:
#include <stdio.h>
#include <math.h>
int qmin(int arr[], int len) {
int min = arr[];
for (int i = 1; i < len; i++) {
if (arr[i] < min) {
min = arr[i];
}
}
return min;
}
int main() {
int y[50];
for (int j = ; j < 50; j++) {
y[j] = 600 * sin(j * .16);
}
int min = qmin(y, 50);
printf("数组中的最小元素为:%d\n", min);
return ;
}
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