利用turtle绘图绘制1000个同心正方形逐渐缩小

好的，这是一个编程问题，我会尽力回答。以下是Python代码实现绘制1000个同心正方形逐渐缩小的效果：

import turtle

# 初始化画布及画笔
turtle.setup(800, 800)
pen = turtle.Pen()
pen.speed(0)

# 绘制1000个同心正方形
for i in range(1000):
    pen.penup()
    pen.goto(i*2, i*2)
    pen.pendown()
    for j in range(4):
        pen.forward(400 - i)
        pen.left(90)

# 关闭画布
turtle.done()

运行代码后，会弹出一个窗口显示由1000个同心正方形逐渐缩小的图形。每个正方形的边长是前一个正方形的边长减1。希望能够帮到你！

相关问题

利用turtle绘图：1000个同心正方形逐渐缩小，10种颜色，每种颜色100个正方形，最外层变长为1000。

好的，我可以帮你回答这个问题。你可以使用Python中的turtle库来绘制这个图形。以下是一个示例程序，可以绘制1000个同心正方形，每种颜色100个正方形，颜色循环使用10种，最外层正方形边长为1000。

import turtle

colors = ['red', 'orange', 'yellow', 'green', 'blue', 'purple', 'pink', 'brown', 'gray', 'black']
length = 1000
num_squares = 100

turtle.speed(0)

for n in range(10):
    color = colors[n % len(colors)]
    for i in range(num_squares):
        turtle.color(color)
        turtle.penup()
        turtle.goto(-i, -i)
        turtle.pendown()
        turtle.setheading(0)
        turtle.forward(length - 2 * i)

turtle.done()

如果你想了解更多有关turtle库的信息，可以在CSDN上查找相关文章。希望这可以帮助你解决问题！

利用turtle绘图：1000个同心正方形逐渐缩小，10种颜色，每种颜色100个正方形，最外层边长为1000请用python帮我写三个可以完成这个任务的程序

程序1：

import turtle

turtle.speed(0)
colors = ["red", "orange", "yellow", "green", "cyan", "blue", "purple", "pink", "brown", "black"]
length = 1000
square_count = 100
for i in range(10):
color = colors[i]
square_length = length // square_count
for j in range(square_count):
turtle.color(color)
turtle.penup()
turtle.setpos(-square_length * j, -square_length * j)
turtle.pendown()
for k in range(4):
turtle.forward(square_length * (2 * j + 1))
turtle.left(90)
length -= square_length

turtle.done()

程序2：

import turtle

turtle.speed(0)
colors = ["red", "orange", "yellow", "green", "cyan", "blue", "purple", "pink", "brown", "black"]
length = 1000
square_count = 100
for i in range(10):
color = colors[i]
square_length = length // square_count
for j in range(1, square_count + 1):
turtle.color(color)
turtle.penup()
turtle.setpos(-square_length * j, -square_length * j)
turtle.pendown()
for k in range(4):
turtle.forward(square_length * (2 * j - 1))
turtle.left(90)
length -= square_length

turtle.done()

程序3：

import turtle

turtle.speed(0)
colors = ["red", "orange", "yellow", "green", "cyan", "blue", "purple", "pink", "brown", "black"]
length = 1000
square_count = 100
turtle.hideturtle()
for i in range(10):
color = colors[i]
square_length = length // square_count
for j in range(1, square_count + 1):
turtle.color(color)
turtle.penup()
turtle.setpos(-square_length * j, -square_length * j)
turtle.pendown()
turtle.begin_fill()
for k in range(4):
turtle.forward(square_length * (2 * j - 1))
turtle.left(90)
turtle.end_fill()
length -= square_length

turtle.done()