Write the methods with the following headers // Return the reversal of an integer, i.e., reverse(456) returns 654 int reverse(int number) // Return true if number is a palindrome int isPalindrome(int number) Use the reverse method to implement isPalindrome. A number is a palindrome if its reversal is the same as itself. Write a test program that prompts the user to enter an integer and reports whether the integer is a palindrome.

Sure! Here are the methods you requested:

public static int reverse(int number) {
    int reversedNumber = 0;
    while (number != 0) {
        reversedNumber = reversedNumber * 10 + number % 10;
        number /= 10;
    }
    return reversedNumber;
}

public static boolean isPalindrome(int number) {
    return number == reverse(number);
}

And here's a program that uses these methods to check if a user-entered integer is a palindrome:

import java.util.Scanner;

public class PalindromeChecker {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.print("Enter an integer: ");
        int number = input.nextInt();
        
        if (isPalindrome(number)) {
            System.out.println(number + " is a palindrome");
        } else {
            System.out.println(number + " is not a palindrome");
        }
    }
}

Hope this helps! Let me know if you have any further questions.