def dec2bin(n, count=8): """returns the binary of integer n, using count number of digits""" return [int((n >> y) & 1) for y in range(count-1, -1, -1)] def dec2binAry(x, bits): mask = np.expand_dims(2**np.arange(bits-1,-1,-1),1).T return (np.bitwise_and(np.expand_dims(x,1), mask)!=0).astype(int) def bin2decAry(x): if(x.ndim==1): x = np.expand_dims(x,0) bits = x.shape[1] mask = np.expand_dims(2**np.arange(bits-1,-1,-1),1) return x.dot(mask).astype(int) def Morton(A): A = A.astype(int) n = np.ceil(np.log2(np.max(A)+1)).astype(int) x = dec2binAry(A[:,0],n) y = dec2binAry(A[:,1],n) z = dec2binAry(A[:,2],n) m = np.stack((x,y,z),2) m = np.transpose(m,(0, 2, 1)) mcode = np.reshape(m,(A.shape[0],3*n),order='F') return mcode
时间: 2024-01-02 20:03:08 浏览: 30
这是一些用于二进制转换和Morton编码的函数。以下是每个函数的功能说明:
1. `dec2bin(n, count=8)`: 将整数n转换为二进制表示,返回一个包含count个二进制位的列表。
2. `dec2binAry(x, bits)`: 将整数x转换为bits位的二进制数组。使用了位掩码和按位与操作来实现。
3. `bin2decAry(x)`: 将二进制数组x转换为对应的整数。使用了位权重和点积运算来实现。
4. `Morton(A)`: 对输入的三维坐标数组A进行Morton编码。首先确定编码所需的位数n,然后将每个坐标分别转换为n位的二进制数组。最后将这些二进制数组按照一定顺序组合成Morton编码。
这些函数可以用于处理二进制转换和Morton编码的任务。
相关问题
检查代码并修改:def BinarySearch(alist,item): index = len(alist) if index == 0: return False else: midpoint = index // 2 if alist[index] == item: return True else: if alist[midpoint] != item: return binarySearch(alist,item)
修改后的代码如下:
def binarySearch(alist, item):
index = len(alist)
if index == 0:
return False
else:
midpoint = index // 2
if alist[midpoint] == item:
return True
else:
if item < alist[midpoint]:
return binarySearch(alist[:midpoint], item)
else:
return binarySearch(alist[midpoint+1:], item)
这是一个递归实现的二分查找算法,原代码中有几个错误,已经进行了修正。
Write a javascript function that takes an integer as input, and returns the number of bits that are equal to one in the binary representation of that number. You can guarantee that input is non-negative. Example: The binary representation of 1234 is 10011010010, so the function should return 5 in this case
Sure, here's a JavaScript function that takes an integer as input and returns the number of bits that are equal to one in its binary representation:
```javascript
function countBits(num) {
// Convert the number to binary string
let binary = num.toString(2);
// Count the number of ones in the binary string
let count = 0;
for (let i = 0; i < binary.length; i++) {
if (binary[i] === '1') {
count++;
}
}
return count;
}
```
You can call this function with an integer as input, like this:
```javascript
console.log(countBits(1234)); // Output: 5
```
This will output `5`, which is the number of bits that are equal to one in the binary representation of `1234`.