Order order=orderService.findOrderById(oid); List<Goods>goodsList=order.getGoodsList(); for (Goods goods:goodsList) { if(goods.getId()==gid){ System.out.println(gid+"----------------------------------------+++++++++++++++++++++++++++++++"); goodsList.remove(goods); break; } } order.setGoodsList(goodsList); orderService.save(order); System.out.println(orderService.findOrderById(oid).getGoodsList()); if(order.getGoodsList().size()==0){ orderService.deleteOrderById(oid); return Result.success(true); } order.setGoodsList(goodsList); return Result.success(true); }这段代码报不能删除

这段代码报错的原因可能是在对 `goodsList` 进行遍历删除时，使用了 `remove` 方法，这样会改变集合的大小，导致遍历出现问题。可以考虑使用迭代器或者倒序遍历来避免这个问题，例如：

Iterator<Goods> iterator = goodsList.iterator();
while (iterator.hasNext()) {
    Goods goods = iterator.next();
    if (goods.getId() == gid) {
        iterator.remove();
        break;
    }
}

或者：

for (int i = goodsList.size() - 1; i >= 0; i--) {
    Goods goods = goodsList.get(i);
    if (goods.getId() == gid) {
        goodsList.remove(i);
        break;
    }
}

另外，注意在删除商品后要判断 `goodsList` 是否为空，可以改为 `if (goodsList.isEmpty())`。最后，不需要再次设置 `order.setGoodsList(goodsList)`，因为已经在删除商品时修改了 `order` 的 `goodsList`。