flutter 如何将多个{"conditionId": "", "deviceId": 1663743185928585216, "ieeeAddress": "CC86ECFFFE5CDCD9", "endpoint": 4, "deviceType": "A010401000000", "state": 1, "temperature": 0, "humidity": 0, "cron": "*"}添加为一个数组

可以使用List来存储多个相同结构的Map。在Flutter中，可以这样定义一个包含多个相同结构Map的List：

List<Map<String, dynamic>> dataList = [
  {"conditionId": "", "deviceId": 1663743185928585216, "ieeeAddress": "CC86ECFFFE5CDCD9", "endpoint": 4, "deviceType": "A010401000000", "state": 1, "temperature": 0, "humidity": 0, "cron": "*"},
  {"conditionId": "", "deviceId": 1663743185928585217, "ieeeAddress": "CC86ECFFFE5CDCD8", "endpoint": 4, "deviceType": "A010401000000", "state": 1, "temperature": 0, "humidity": 0, "cron": "*"},
  {"conditionId": "", "deviceId": 1663743185928585218, "ieeeAddress": "CC86ECFFFE5CDCD7", "endpoint": 4, "deviceType": "A010401000000", "state": 1, "temperature": 0, "humidity": 0, "cron": "*"}
];

在这个例子中，我们定义了一个包含三个相同结构的Map的List，每个Map包含了conditionId、deviceId、ieeeAddress等相同的key-value对。你可以根据需要修改Map中的值，或者添加/删除Map来实现你的需求。