9.18362E-40 转为2进制
时间: 2023-10-09 21:10:47 浏览: 56
由于9.18362E-40是一个非常小的数,它的二进制表示需要用到科学计数法,即先将9.18362E-40表示为1.xxxxxx乘以2的负n次方的形式,其中1.xxxxxx是一个小于1的数,n是一个正整数。
首先,将9.18362E-40表示为1.xxxxxx乘以2的负n次方的形式,可以得到:
9.18362E-40 = 1.1100010110100110111011011101111100000101111000010111 × 2的负132次方
其中,1.xxxxxx的值为1.1100010110100110111011011101111100000101111000010111(保留小数点后面的位数可以适当增加或减少,这里只保留了16位)。因此,将这个数转换为二进制,得到:
1.1100010110100110111011011101111100000101111000010111 = 0.00000000000000000000000000000000000000000000000111011110111101101101101001101000101111100000101110
最后,将该二进制数与2的负132次方相乘,即在二进制数的末尾添加132个0,得到最终结果:
9.18362E-40 = 0.00000000000000000000000000000000000000000000000111011110111101101101101001101000101111100000101110 × 2的负132次方
= 0.00000000000000000000000000000000000000000000000111011110111101101101101001101000101111100000101110 × 2的负10000100次方
= 0.00000000000000000000000000000000000000000000000111011110111101101101101001101000101111100000101110 × 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001
= 0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000111011110111101101101101001101000101111100000101110