C语言编程判断输入整数x的正负性和奇偶性。 **输入格式要求:"%d" 提示信息:"Enter a integer:" **输出格式要求:"The integer is a plus even number\n" "This integer is a plus odd number\n" "This integer is a minus even number\n" "This integer is a minus odd number\n" "This integer is zero.\
时间: 2023-06-26 11:06:10 浏览: 141
以下是 C 语言代码实现:
```c
#include <stdio.h>
int main() {
int x;
printf("Enter an integer: ");
scanf("%d", &x);
if (x > 0) {
if (x % 2 == 0) {
printf("The integer is a plus even number\n");
} else {
printf("This integer is a plus odd number\n");
}
} else if (x < 0) {
if (x % 2 == 0) {
printf("This integer is a minus even number\n");
} else {
printf("This integer is a minus odd number\n");
}
} else {
printf("This integer is zero.\n");
}
return 0;
}
```
代码逻辑比较简单,就是先判断正负性,再判断奇偶性,最后输出相应的结果。其中 `%d` 表示输入的是整数,`scanf` 函数用于输入。输出格式要求依次判断即可。
相关问题
编程判断输入整数x的正负性和奇偶性。 **输入格式要求:"%d" 提示信息:"Enter a integer:" **输出格式要求:"The integer is a plus even number\n" "This integer is a plus odd number\n" "This integer is a minus even number\n" "This integer is a minus odd number\n" "This integer is zero.\n"
好的,以下是对应的C语言代码:
```c
#include <stdio.h>
int main() {
int x;
printf("Enter a integer:");
scanf("%d", &x);
// 判断正负性和奇偶性
if (x > 0) {
if (x % 2 == 0) {
printf("The integer is a plus even number\n");
} else {
printf("This integer is a plus odd number\n");
}
} else if (x < 0) {
if (x % 2 == 0) {
printf("This integer is a minus even number\n");
} else {
printf("This integer is a minus odd number\n");
}
} else {
printf("This integer is zero.\n");
}
return 0;
}
```
希望能对你有所帮助!
C语言从键盘任意输入一个整数,编程判断它的奇偶性。 **输入格式要求:"%d" 提示信息:"Input an integer number:" **输出格式要求:"a is an even number\n" "a is an odd number\n"
以下是实现功能的C语言代码:
```
#include <stdio.h>
int main() {
int a;
printf("Input an integer number:");
scanf("%d", &a);
if (a % 2 == 0) {
printf("%d is an even number\n", a);
} else {
printf("%d is an odd number\n", a);
}
return 0;
}
```
程序首先提示用户输入一个整数,然后使用 `scanf` 函数读取输入的数字。接着使用 `if` 语句判断输入的数字是否为偶数,如果是偶数,则输出结果为 "a is an even number",否则输出结果为 "a is an odd number"。最后程序返回0,表示正常结束。
阅读全文