4轮des算法的差分分析的c语言代码
时间: 2024-03-19 12:44:07 浏览: 75
基于C++进行六轮 DES 算法的差分分析【100013174】
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以下是一个基本的4轮DES算法的差分分析C语言代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/* 4轮DES算法的S盒 */
int SBox[8][4][16] = {
{
{14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7},
{0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8},
{4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0},
{15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13}
},
{
{15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10},
{3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5},
{0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15},
{13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9}
},
{
{10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8},
{13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1},
{13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7},
{1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12}
},
{
{7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15},
{13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9},
{10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4},
{3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14}
},
{
{2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9},
{14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6},
{4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14},
{11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3}
},
{
{12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11},
{10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8},
{9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6},
{4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13}
},
{
{4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1},
{13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6},
{1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2},
{6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12}
},
{
{13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7},
{1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2},
{7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8},
{2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11}
}
};
/* 4轮DES算法的P盒 */
int PBox[32] = {16, 7, 20, 21, 29, 12, 28, 17, 1, 15, 23, 26, 5, 18, 31, 10,
2, 8, 24, 14, 32, 27, 3, 9, 19, 13, 30, 6, 22, 11, 4, 25};
/* 差分分析函数 */
void differential_analysis(int diff_in, int diff_out, int keys[])
{
int i, j;
int count[64] = {0}; /* 统计每个密钥出现的次数 */
/* 遍历所有可能的第1轮子密钥 */
for (i = 0; i < 64; i++) {
int key1 = i << 1; /* 将6位密钥扩展为8位 */
int key2 = key1 | (key1 >> 5); /* 循环左移1位 */
int subkey1 = key2 & 0x3f; /* 取低6位作为第1轮子密钥 */
int subkey2 = (key2 >> 6) & 0x3f; /* 取高6位作为第2轮子密钥 */
/* 遍历所有可能的第2轮子密钥 */
for (j = 0; j < 64; j++) {
int subkey3 = j & 0x3f; /* 取低6位作为第3轮子密钥 */
int subkey4 = (j >> 6) & 0x3f; /* 取高6位作为第4轮子密钥 */
int k;
int cnt = 0;
/* 遍历所有可能的64位密钥 */
for (k = 0; k < 64; k++) {
int key = k;
/* 进行4轮加密 */
key = (key ^ subkey1) & 0x3f;
key = SBox[0][key >> 4][key & 0x0f];
key = (key ^ subkey2) & 0x3f;
key = SBox[1][key >> 4][key & 0x0f];
key = (key ^ subkey3) & 0x3f;
key = SBox[2][key >> 4][key & 0x0f];
key = (key ^ subkey4) & 0x3f;
key = SBox[3][key >> 4][key & 0x0f];
key = (key << 1) | (key >> 5);
key = key ^ subkey1;
/* 判断差分是否满足要求 */
if (((key ^ (key ^ diff_in)) & 0x3f) == diff_in) {
/* 进行P盒置换 */
int out = 0;
int x;
for (x = 0; x < 32; x++) {
out |= ((key >> (32 - PBox[x])) & 0x01) << (31 - x);
}
/* 统计密钥出现的次数 */
count[(out ^ (out ^ diff_out)) >> 26]++;
cnt++;
}
}
/* 输出当前轮的结果 */
printf("subkey1=%02x, subkey2=%02x, subkey3=%02x, subkey4=%02x, count=%d\n",
subkey1, subkey2, subkey3, subkey4, cnt);
}
}
/* 输出结果 */
printf("Key\tCount\n");
for (i = 0; i < 64; i++) {
printf("%02x\t%d\n", keys[i], count[i]);
}
}
int main()
{
int diff_in = 0x00000001; /* 明文差分 */
int diff_out = 0x08000000; /* 密文差分 */
int keys[64] = {0}; /* 所有可能的密钥 */
int i;
for (i = 0; i < 64; i++) {
keys[i] = i;
}
differential_analysis(diff_in, diff_out, keys);
return 0;
}
```
这个代码实现了4轮DES算法的差分分析,其中包含了S盒和P盒的定义。您可以根据需要修改输入输出差分和密钥长度,并根据需要输出统计结果。
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