void mergeSort(int* nums, int begin, int end) { if (begin >= end) { return; } int len = end - begin+1; int mid = begin + (end - begin) / 2; mergeSort(nums, begin, mid); mergeSort(nums, mid+1, end); int* temp = new int[len]; temp = { 0 }; int l1 = begin, r1 = mid; int l2 = mid+1, r2 = end; int i = begin; for (; l1 <= r1 && l2 <= r2;) { if (nums[l1] < nums[l2]) { temp[i++] = nums[l1++]; } else { temp[i++] = nums[l2++]; } } for (; l1 <= r1;) { temp[i++] = nums[l1++]; } for (; l2 <= r2;) { temp[i++] = nums[l2++]; } for (int j = 0; j < len; j++) { nums[j+begin] = temp[j]; } } 出现读取访问冲突，修改代码

在代码中，`temp`被赋值为一个新的`int`数组，然后又被赋值为`{0}`，这样会导致`temp`指向了一个新的内存地址，原有的内存地址被泄漏。在后续的代码中，程序又对这个新的内存地址进行了读写操作，从而导致了读取访问冲突。为了解决这个问题，应该在申请`int`数组的同时，将数组中的元素全部初始化为0。修改后的代码如下：

void mergeSort(int* nums, int begin, int end) {
    if (begin >= end) {
        return;
    }
    int len = end - begin+1;
    int mid = begin + (end - begin) / 2;
    mergeSort(nums, begin, mid);
    mergeSort(nums, mid+1, end);

    int* temp = new int[len](); // 将数组中的元素全部初始化为0
    int l1 = begin, r1 = mid;
    int l2 = mid+1, r2 = end;
    int i = begin;
    for (; l1 <= r1 && l2 <= r2;) {
        if (nums[l1] < nums[l2]) {
            temp[i++] = nums[l1++];
        }
        else {
            temp[i++] = nums[l2++];
        }
    }
    for (; l1 <= r1;) { temp[i++] = nums[l1++]; }
    for (; l2 <= r2;) { temp[i++] = nums[l2++]; }

    for (int j = 0; j < len; j++) {
        nums[j+begin] = temp[j];
    }

    delete[] temp; // 释放动态申请的内存空间
}