用C语言写一个打开jpg图像并且显示其像素点矩阵的代码

以下是用C语言打开jpg图像并显示其像素点矩阵的代码：

#include <stdio.h>
#include <stdlib.h>
#include <jpeglib.h>

int main(int argc, char *argv[]) {
    if (argc != 2) {
        printf("Usage: %s <filename>\n", argv[0]);
        return 1;
    }

    char *filename = argv[1];
    FILE *file = fopen(filename, "rb");
    if (!file) {
        printf("Failed to open file: %s\n", filename);
        return 1;
    }

    struct jpeg_decompress_struct cinfo;
    struct jpeg_error_mgr jerr;

    cinfo.err = jpeg_std_error(&jerr);
    jpeg_create_decompress(&cinfo);
    jpeg_stdio_src(&cinfo, file);
    jpeg_read_header(&cinfo, TRUE);
    jpeg_start_decompress(&cinfo);

    int row_stride = cinfo.output_width * cinfo.output_components;
    unsigned char *buffer = (unsigned char*)malloc(row_stride);
    while (cinfo.output_scanline < cinfo.output_height) {
        jpeg_read_scanlines(&cinfo, &buffer, 1);
        for (int i = 0; i < row_stride; i++) {
            printf("%d ", buffer[i]);
        }
        printf("\n");
    }

    free(buffer);
    jpeg_finish_decompress(&cinfo);
    jpeg_destroy_decompress(&cinfo);
    fclose(file);

    return 0;
}

这段代码使用了libjpeg库来解码jpg图像，首先打开文件，然后创建一个jpeg解码器，读取图像头部信息，开始解码，逐行读取像素点数据并输出到控制台，最后释放内存并关闭文件。