C语言编程判断输入整数x的正负性和奇偶性。 **输入格式要求："%d" 提示信息："Enter a integer:" **输出格式要求："The integer is a plus even number\n" "This integer is a plus odd number\n" "This integer is a minus even number\n" "This integer is a minus odd number\n" "This integer is zero.\n" 程序运行示例如下： Enter a integer:-9 This integer is a minus odd number

下面是一个示例代码实现：

#include <stdio.h>

int main() {
    int x;
    printf("Enter a integer:");
    scanf("%d", &x);

    if (x > 0) { // 正数
        if (x % 2 == 0) { // 偶数
            printf("This integer is a plus even number\n");
        } else { // 奇数
            printf("This integer is a plus odd number\n");
        }
    } else if (x < 0) { // 负数
        if (x % 2 == 0) { // 偶数
            printf("This integer is a minus even number\n");
        } else { // 奇数
            printf("This integer is a minus odd number\n");
        }
    } else { // 零
        printf("This integer is zero.\n");
    }

    return 0;
}

运行结果：

Enter a integer:-9
This integer is a minus odd number