IF EXISTS ( SELECT COUNT( 1 ) AS count FROM ( SELECT t822.order_plan_id, overview.order_plan_id AS ovid, overview.hr_request_number, overview.hr_request_title, overview.response_deadline, overview.hr_request_create_office_group_code, overview.update_datetime FROM t_hr_request_overview overview LEFT JOIN tb_0080022_dt_pc_order_management t822 ON overview.order_plan_id = t822.order_plan_id WHERE t822.order_plan_id = "#000000639201" ) select_count )THEN SELECT TRUE AS result; ELSE SELECT FALSE AS result END IF 修改成正确代码

时间: 2023-08-18 14:04:25 浏览: 19
根据您提供的代码,以下是修改后的正确代码: ```sql DECLARE @count INT; SELECT @count = COUNT(*) FROM ( SELECT t822.order_plan_id, overview.order_plan_id AS ovid, overview.hr_request_number, overview.hr_request_title, overview.response_deadline, overview.hr_request_create_office_group_code, overview.update_datetime FROM t_hr_request_overview overview LEFT JOIN tb_0080022_dt_pc_order_management t822 ON overview.order_plan_id = t822.order_plan_id WHERE t822.order_plan_id = '#000000639201' ) AS select_count; IF @count > 0 THEN SELECT 'true' AS result; ELSE SELECT 'false' AS result; END IF; ``` 在上述代码中,我们使用变量 `@count` 来存储查询结果的行数,并通过 IF-ELSE 语句来判断是否为空。如果 `@count` 大于 0,则返回 true;否则,返回 false。 请注意,具体的实现方式可能根据您所使用的数据库类型和编程语言有所不同。您需要将其适配到您所使用的数据库和编程环境中。

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优化这个sql SELECT count( 1 ) FROM ( SELECT B.ID, B.PURCHASE_REQUEST_ID, B.MATERIAL_ID, B.MATERIAL_CODE, B.MATERIAL_NAME, B.STANDARD, B.MODEL_ID, B.BILL_ROW_ID, B.BILL_NO, BILL_NAME, B.MODEL_CODE, B.MODEL_NAME, B.PARENT_MODEL_ID, B.PARENT_MODEL_CODE, B.PARENT_MODEL_NAME, B.UNIT_CODE, B.UNIT_NAME, B.PURCHASE_TYPE_CODE, CAST( NVL( B.APPLY_NUM, 0 ) AS NUMBER ( 24, 10 ) ) AS APPLY_NUM, CAST( NVL( B.DEAL_NUM, 0 ) AS NUMBER ( 24, 10 ) ) AS DEAL_NUM, CAST( NVL( B.RETURN_NUM, 0 ) AS NUMBER ( 24, 10 ) ) AS RETURN_NUM, B.DEAL_USER_ID, B.DEAL_USER_NAME, CAST( NVL( B.PRICE, 0 ) AS NUMBER ( 24, 10 ) ) AS PRICE, CAST( NVL( B.AMOUNT, 0 ) AS NUMBER ( 24, 10 ) ) AMOUNT, B.IMPLEMENT_CODE, B.IMPLEMENT_NAME, B.IMPLEMENT_INVEST_AMOUNT, B.PURCHASE_MANAGER_ID, B.PURCHASE_MANAGER_NAME, B.PROVIDER_ID, B.PROVIDER_NAME, B.REMARK, B.DELIVER_AREA, B.DELIVER_ADDRESS, B.RECEIVE_PEOPLE, B.RECEIVE_PEOPLE_PHONE, B.ITEM_STATUS, B.COST_CENTER, B.COST_BUDGET_CODE, B.COST_IMPLEMENT_NAME, B.FRAME_CONT_ID, B.FRAME_CONT_CODE, B.FRAME_CONT_NAME, B.DETAIL_CONFIG, B.PURCHASE_CATEGORY_CODE, B.INVOICE_TITLE_CODE, B.INVOICE_SEND_ADDRRSS, B.MATERIAL_REQUEST_ITEM_ID, B.YEAR, B.DELETE_FLAG, B.PROVINCE_CODE, B.REASON, B.PARENT_ITEM_ID, B.FRAME_CONT_ITEM_ID, B.SUB_MATERIAL_REQUEST_ID, B.SUB_MATERIAL_REQUEST_CODE, B.MATERIAL_URL, B.RECOMMEND_PROVIDER_NAMES, C.PURCHASE_REQUEST_CODE, C.PURCHASE_REQUEST_NAME, C.APPLY_TYPE_CODE, C.CREATOR_NAME, C.APPLY_TELEPHONE, C.COMPANY_NAME, C.DEPT_NAME, B.CREATE_TIME, TO_CHAR( B.CREATE_TIME, 'YYYY-MM-DD' ) CREATE_TIME_STR, C.ARRIVE_TIME, C.IS_TO_END, C.MONEY_WAY_CODE, C.OWN, C.APPLY_CATEGORY_CODE, C.manu_Type, C.BILL_ID, MMD.MATERIAL_TYPE_CODE, B.BRANCH_COMPANY_DEAL_USER_ID, B.BRANCH_COMPANY_DEAL_USER_NAME, ( SELECT ORG_NAME FROM ORGANIZATIONS WHERE DELETE_FLAG = '0' AND ORG_CODE = ( SELECT PARENT_COMPANY_NO FROM ORGANIZATIONS WHERE ID = B.MATERIAL_DEPT_ID )) AS MATERIAL_COMPANY_NAME, B.ORIGINAL, B.PROVIDER_PRODUCT_MODEL, B.PROVIDER_PRODUCT_NAME, B.PRODUCT_DESC, B.Back_Flag, CASE WHEN MMD.material_type_code = 'WZ' THEN '1' WHEN MMD.material_type_code = 'FW' THEN '2' ELSE '3' END apply_category_code_item, NVL( C.IS_CARDSYSTEM_REQUEST, '0' ) IS_CARDSYSTEM_REQUEST, B.APPLY_GROUP_AUTHORITES, B.SCIENTIFIC_RESEARCH_ID, B.SCIENTIFIC_RESEARCH_CODE, B.SCIENTIFIC_RESEARCH_NAME, B.PREQUALFY_CODE, nvl( C.IS_QUICK, '0' ) AS IS_QUICK, C.PURCHASE_WAY_CODE, C.PURCHASE_TYPE_CODE PURCHASE_TYPE_CODE_P, C.ORIGINAL_TYPE, C.PURCHASE_REQUEST_BILLS_TYPE, B.IS_FRAME_CONT_MONAD FROM PURCHASE_REQUEST_ITEM B LEFT JOIN PURCHASE_REQUEST C ON B.PURCHASE_REQUEST_ID = C.ID LEFT JOIN MATERIAL_DATA MMD ON MMD.ID = B.MATERIAL_ID AND MMD.DELETE_FLAG = '0' WHERE B.delete_flag = '0' AND B.Item_Status IN ( 1 ) AND NOT EXISTS ( SELECT * FROM purchase_request_item_log pril WHERE B.id = pril.purchase_request_item_id AND pril.lock_status = '1' AND pril.delete_flag = '0' ) AND ( ( c.apply_type_code NOT IN ( '20', '41', '3' ) AND nvl( B.Apply_Num, 0 ) > nvl( B.Deal_Num, 0 )) OR c.apply_type_code IN ( '20', '41', '3' ) ) AND B.Deal_User_Id =: 1 AND C.MONEY_WAY_CODE =: 2 AND C.APPLY_TYPE_CODE =: 3 AND C.PAY_OUT_TYPE_CODE =: 4 AND C.APPLY_CATEGORY_CODE =: 5 AND NVL( C.IS_CARDSYSTEM_REQUEST, '0' ) = : 6 AND NOT EXISTS ( SELECT * FROM purchase_request_item p left join material_province mp ON p.material_id = mp.material_id WHERE p.delete_flag = 0 AND mp.delete_flag = 0 AND mp.material_status = 03 AND mp.org_code = p.province_code AND p.id = B.id ) ORDER BY C.ID, B.ID ASC)

首先,可以将子查询中的所有列名改为别名,这样可以避免重名和提高代码可读性。另外,可以尝试使用 EXISTS 子查询来替换 NOT EXISTS 子查询,因为 EXISTS 子查询的性能通常更好。最后,可以考虑对 WHERE 子句中的多个条件进行逻辑上的分组,以避免出现过于复杂的条件表达式。下面是优化后的 SQL: SELECT COUNT(1) FROM ( SELECT b.ID, b.PURCHASE_REQUEST_ID, b.MATERIAL_ID, b.MATERIAL_CODE, b.MATERIAL_NAME, b.STANDARD, b.MODEL_ID, b.BILL_ROW_ID, b.BILL_NO, b.BILL_NAME, b.MODEL_CODE, b.MODEL_NAME, b.PARENT_MODEL_ID, b.PARENT_MODEL_CODE, b.PARENT_MODEL_NAME, b.UNIT_CODE, b.UNIT_NAME, b.PURCHASE_TYPE_CODE, CAST(NVL(b.APPLY_NUM, 0) AS NUMBER(24, 10)) AS APPLY_NUM, CAST(NVL(b.DEAL_NUM, 0) AS NUMBER(24, 10)) AS DEAL_NUM, CAST(NVL(b.RETURN_NUM, 0) AS NUMBER(24, 10)) AS RETURN_NUM, b.DEAL_USER_ID, b.DEAL_USER_NAME, CAST(NVL(b.PRICE, 0) AS NUMBER(24, 10)) AS PRICE, CAST(NVL(b.AMOUNT, 0) AS NUMBER(24, 10)) AMOUNT, b.IMPLEMENT_CODE, b.IMPLEMENT_NAME, b.IMPLEMENT_INVEST_AMOUNT, b.PURCHASE_MANAGER_ID, b.PURCHASE_MANAGER_NAME, b.PROVIDER_ID, b.PROVIDER_NAME, b.REMARK, b.DELIVER_AREA, b.DELIVER_ADDRESS, b.RECEIVE_PEOPLE, b.RECEIVE_PEOPLE_PHONE, b.ITEM_STATUS, b.COST_CENTER, b.COST_BUDGET_CODE, b.COST_IMPLEMENT_NAME, b.FRAME_CONT_ID, b.FRAME_CONT_CODE, b.FRAME_CONT_NAME, b.DETAIL_CONFIG, b.PURCHASE_CATEGORY_CODE, b.INVOICE_TITLE_CODE, b.INVOICE_SEND_ADDRRSS, b.MATERIAL_REQUEST_ITEM_ID, b.YEAR, b.DELETE_FLAG, b.PROVINCE_CODE, b.REASON, b.PARENT_ITEM_ID, b.FRAME_CONT_ITEM_ID, b.SUB_MATERIAL_REQUEST_ID, b.SUB_MATERIAL_REQUEST_CODE, b.MATERIAL_URL, b.RECOMMEND_PROVIDER_NAMES, c.PURCHASE_REQUEST_CODE, c.PURCHASE_REQUEST_NAME, c.APPLY_TYPE_CODE, c.CREATOR_NAME, c.APPLY_TELEPHONE, c.COMPANY_NAME, c.DEPT_NAME, b.CREATE_TIME, TO_CHAR(b.CREATE_TIME, 'YYYY-MM-DD') CREATE_TIME_STR, c.ARRIVE_TIME, c.IS_TO_END, c.MONEY_WAY_CODE, c.OWN, c.APPLY_CATEGORY_CODE, c.manu_Type, c.BILL_ID, MMD.MATERIAL_TYPE_CODE, b.BRANCH_COMPANY_DEAL_USER_ID, b.BRANCH_COMPANY_DEAL_USER_NAME, (SELECT ORG_NAME FROM ORGANIZATIONS WHERE DELETE_FLAG = '0' AND ORG_CODE = (SELECT PARENT_COMPANY_NO FROM ORGANIZATIONS WHERE ID = b.MATERIAL_DEPT_ID)) AS MATERIAL_COMPANY_NAME, b.ORIGINAL, b.PROVIDER_PRODUCT_MODEL, b.PROVIDER_PRODUCT_NAME, b.PRODUCT_DESC, b.Back_Flag, CASE WHEN MMD.material_type_code = 'WZ' THEN '1' WHEN MMD.material_type_code = 'FW' THEN '2' ELSE '3' END apply_category_code_item, NVL(c.IS_CARDSYSTEM_REQUEST, '0') IS_CARDSYSTEM_REQUEST, b.APPLY_GROUP_AUTHORITES, b.SCIENTIFIC_RESEARCH_ID, b.SCIENTIFIC_RESEARCH_CODE, b.SCIENTIFIC_RESEARCH_NAME, b.PREQUALFY_CODE, NVL(c.IS_QUICK, '0') AS IS_QUICK, c.PURCHASE_WAY_CODE, c.PURCHASE_TYPE_CODE PURCHASE_TYPE_CODE_P, c.ORIGINAL_TYPE, c.PURCHASE_REQUEST_BILLS_TYPE, b.IS_FRAME_CONT_MONAD FROM PURCHASE_REQUEST_ITEM b LEFT JOIN PURCHASE_REQUEST c ON b.PURCHASE_REQUEST_ID = c.ID LEFT JOIN MATERIAL_DATA MMD ON MMD.ID = b.MATERIAL_ID AND MMD.DELETE_FLAG = '0' WHERE b.delete_flag = '0' AND b.Item_Status IN (1) AND b.Deal_User_Id = :1 AND C.MONEY_WAY_CODE = :2 AND C.APPLY_TYPE_CODE = :3 AND C.PAY_OUT_TYPE_CODE = :4 AND C.APPLY_CATEGORY_CODE = :5 AND NVL(C.IS_CARDSYSTEM_REQUEST, '0') = :6 AND EXISTS ( SELECT * FROM purchase_request_item_log pril WHERE B.id = pril.purchase_request_item_id AND pril.lock_status = '1' AND pril.delete_flag = '0' ) AND ( c.apply_type_code IN ('20', '41', '3') OR ( c.apply_type_code NOT IN ('20', '41', '3') AND NVL(b.Apply_Num, 0) > NVL(b.Deal_Num, 0) ) ) AND NOT EXISTS ( SELECT * FROM purchase_request_item p LEFT JOIN material_province mp ON p.material_id = mp.material_id WHERE p.delete_flag = 0 AND mp.delete_flag = 0 AND mp.material_status = 03 AND mp.org_code = p.province_code AND p.id = b.id ) ORDER BY c.ID, b.ID ASC )

请将这个存储过程修改为触发器,当其余四个表插入新数据时,t_pcm_prod_own能够修改更新数据 CREATE DEFINER=root@% PROCEDURE test03() BEGIN -- 是否持有活期 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_CURR)) THEN UPDATE T_PCM_PROD_OWN SET IS_DEP = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_CURR); ELSE UPDATE T_PCM_PROD_OWN SET IS_DEP = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_CURR); END IF; -- 是否持有定期 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_FIXED)) THEN UPDATE T_PCM_PROD_OWN SET IS_FIXED_DEP = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_FIXED); ELSE UPDATE T_PCM_PROD_OWN SET IS_FIXED_DEP = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_DEP_FIXED); END IF; -- 是否持有贷款 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_LOAN)) THEN UPDATE T_PCM_PROD_OWN SET IS_LOAN = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_LOAN); ELSE UPDATE T_PCM_PROD_OWN SET IS_LOAN = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_LOAN); END IF; -- 是否持有理财 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_WEALTH)) THEN UPDATE T_PCM_PROD_OWN SET IS_WEALTH = '1' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_WEALTH); ELSE UPDATE T_PCM_PROD_OWN SET IS_WEALTH = '0' WHERE CUST_ID IN (SELECT CUST_ID FROM T_PCM_WEALTH); END IF; INSERT INTO T_PCM_PROD_OWN SELECT REPLACE(UUID(),'-','') ,T_PCM_CUST.CUST_ID ,T_PCM_CUST.LAW_ORG_ID ,T_PCM_CUST.ECIF_CUST_ID ,T_PCM_PROD_OWN.IS_DEP ,T_PCM_PROD_OWN.IS_FIXED_DEP ,T_PCM_PROD_OWN.IS_LOAN ,T_PCM_PROD_OWN.IS_WEALTH ,T_PCM_DEP_CURR.CURRENT_BAL ,T_PCM_DEP_FIXED.BAL ,T_PCM_LOAN.LOAN_MON ,T_PCM_WEALTH.CURRENT_BAL FROM T_PCM_CUST LEFT JOIN T_PCM_DEP_CURR ON T_PCM_CUST.CUST_ID = T_PCM_DEP_CURR.CUST_ID LEFT JOIN T_PCM_DEP_FIXED ON T_PCM_CUST.CUST_ID = T_PCM_DEP_FIXED.CUST_ID LEFT JOIN T_PCM_LOAN ON T_PCM_CUST.CUST_ID = T_PCM_LOAN.CUST_ID LEFT JOIN T_PCM_WEALTH ON T_PCM_CUST.CUST_ID = T_PCM_WEALTH.CUST_ID LEFT JOIN T_PCM_PROD_OWN ON T_PCM_CUST.CUST_ID = T_PCM_PROD_OWN.CUST_ID; END

您好!根据您的要求,将存储过程修改为触发器,当其余四个表插入新数据时,t_pcm_prod_own将能够修改更新数据。以下是修改后的触发器代码: mysql CREATE DEFINER=root@% TRIGGER trg_test03 AFTER INSERT ON T_PCM_DEP_CURR FOR EACH ROW BEGIN -- 是否持有活期 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID = NEW.CUST_ID) THEN UPDATE T_PCM_PROD_OWN SET IS_DEP = '1' WHERE CUST_ID = NEW.CUST_ID; ELSE UPDATE T_PCM_PROD_OWN SET IS_DEP = '0' WHERE CUST_ID = NEW.CUST_ID; END IF; END; CREATE DEFINER=root@% TRIGGER trg_test03_2 AFTER INSERT ON T_PCM_DEP_FIXED FOR EACH ROW BEGIN -- 是否持有定期 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID = NEW.CUST_ID) THEN UPDATE T_PCM_PROD_OWN SET IS_FIXED_DEP = '1' WHERE CUST_ID = NEW.CUST_ID; ELSE UPDATE T_PCM_PROD_OWN SET IS_FIXED_DEP = '0' WHERE CUST_ID = NEW.CUST_ID; END IF; END; CREATE DEFINER=root@% TRIGGER trg_test03_3 AFTER INSERT ON T_PCM_LOAN FOR EACH ROW BEGIN -- 是否持有贷款 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID = NEW.CUST_ID) THEN UPDATE T_PCM_PROD_OWN SET IS_LOAN = '1' WHERE CUST_ID = NEW.CUST_ID; ELSE UPDATE T_PCM_PROD_OWN SET IS_LOAN = '0' WHERE CUST_ID = NEW.CUST_ID; END IF; END; CREATE DEFINER=root@% TRIGGER trg_test03_4 AFTER INSERT ON T_PCM_WEALTH FOR EACH ROW BEGIN -- 是否持有理财 IF EXISTS(SELECT CUST_ID FROM T_PCM_PROD_OWN WHERE CUST_ID = NEW.CUST_ID) THEN UPDATE T_PCM_PROD_OWN SET IS_WEALTH = '1' WHERE CUST_ID = NEW.CUST_ID; ELSE UPDATE T_PCM_PROD_OWN SET IS_WEALTH = '0' WHERE CUST_ID = NEW.CUST_ID; END IF; END; 请注意,每个表都有一个单独的触发器,以确保在插入新数据时更新相应的列。触发器将根据新插入的数据的CUST_ID值来更新t_pcm_prod_own表中的相关列。

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0HAL编号:tel-038172580https://theses.hal.science/tel-038172580提交日期:2022年10月17日0HAL是一个多学科开放获取档案库,用于存储和传播科学研究文档,无论其是否发表。这些文档可以来自法国或国外的教育和研究机构,也可以来自公共或私人研究中心。0HAL多学科开放获取档案库旨在存储和传播法国或国外的教育和研究机构、公共或私人实验室发表或未发表的研究文档。0代理重加密和认证委托的贡献0Anass Sbai0引用此版本:0Anass Sbai. 代理重加密和认证委托的贡献. 离散数学[cs.DM]. 皮卡第朱尔大学, 2021. 法语. �NNT:2021AMIE0032�. �tel-03817258�0博士学位论文0专业“计算机科学”0提交给科技与健康学院博士学位学校0皮卡第朱尔大学0由0Anass SBAI0获得皮卡第朱尔大学博士学位0代理重加密和认证委托的贡献0于2021年7月5日,在评审人的意见后,面向考试委员会进行

c++输入若干不同的整数构成的升序序列,请编写一个程序,找出序列中有多少个数是序列中其他两个数的平均值要求使用算法,使计算量最小,计算时间最短

算法思路: 1. 先将输入的升序序列存储到vector<int>中 2. 枚举每个数,以该数为平均数,查找序列中是否存在两个数的平均值等于该数 3. 可以采用双指针法,从序列的两端开始查找,如果两个指针所指的数的平均值大于目标数,则右指针左移;如果平均值小于目标数,则左指针右移;如果平均值等于目标数,则找到一个符合条件的数 4. 计数器加1,继续枚举下一个数 代码实现如下: ```c++ #include<iostream> #include<vector> using namespace std; int main() { int n; cin >> n;