2. 已知某煤场有 29.5t煤,先用一辆载重4t的汽车运3次,剩下的用一辆载重为 2.5t的汽车运送,请计算还需要运送几次才能送完?编写Python程序,解答此问题
时间: 2024-10-09 10:02:06 浏览: 98
首先,我们可以通过简单的数学计算来确定剩余煤炭的数量,然后除以较小的载重量(2.5吨)来找出所需的次数。接下来,我会为您编写一个Python程序来解决这个问题。
1. 计算第一次3次运输后剩余的煤炭量:
```python
total_coal = 29.5 # 总煤炭量
car_capacity_1 = 4 # 第一辆车的载重量
trips_1 = 3 # 第一辆车的运输次数
coal_after_first_trip = total_coal - (car_capacity_1 * trips_1)
```
2. 然后计算剩下部分需要的运输次数:
```python
car_capacity_2 = 2.5 # 第二辆车的载重量
remaining_trips = 0 # 初始化剩余次数
while coal_after_first_trip >= car_capacity_2:
coal_after_first_trip -= car_capacity_2
remaining_trips += 1
```
3. 最后,打印结果:
```python
print("还需要运送", remaining_trips, "次才能送完")
```
现在,我将把这些代码组合在一起:
```python
def calculate_remaining_trips(total_coal, car_capacity_1, trips_1, car_capacity_2):
coal_after_first_trip = total_coal - (car_capacity_1 * trips_1)
remaining_trips = 0
while coal_after_first_trip >= car_capacity_2:
coal_after_first_trip -= car_capacity_2
remaining_trips += 1
return remaining_trips
total_coal = 29.5
car_capacity_1 = 4
trips_1 = 3
car_capacity_2 = 2.5
remaining_trips = calculate_remaining_trips(total_coal, car_capacity_1, trips_1, car_capacity_2)
print("还需要运送", remaining_trips, "次才能送完")
```
运行这个程序后,它会输出所需额外运输的次数。请注意,由于实际运算结果可能会是小数,这里通常只保留整数次运输。
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