如何用outtextxy将结构数组中的内容输出
时间: 2024-04-13 16:30:57 浏览: 360
使用`outtextxy`函数将结构数组中的内容输出需要进行以下步骤:
1. 在绘图窗口中设置绘图窗口的大小和位置,可以使用`initgraph`函数进行初始化。
```cpp
int gd = DETECT, gm;
initgraph(&gd, &gm, ""); // 初始化绘图窗口
```
2. 定义一个结构体类型,并创建结构数组。
```cpp
struct Student {
char name[20];
int age;
};
Student students[3];
```
3. 给结构数组赋值。
```cpp
strcpy(students[0].name, "Alice");
students[0].age = 18;
strcpy(students[1].name, "Bob");
students[1].age = 19;
strcpy(students[2].name, "Charlie");
students[2].age = 20;
```
4. 使用`outtextxy`函数将结构数组中的内容输出到绘图窗口。
```cpp
for (int i = 0; i < 3; i++) {
outtextxy(100, 100 + i * 20, students[i].name); // 输出姓名
char ageStr[5];
sprintf(ageStr, "%d", students[i].age); // 将年龄转换为字符串
outtextxy(200, 100 + i * 20, ageStr); // 输出年龄
}
```
完整的示例代码如下:
```cpp
#include <graphics.h>
#include <stdio.h>
#include <string.h>
struct Student {
char name[20];
int age;
};
int main() {
int gd = DETECT, gm;
initgraph(&gd, &gm, ""); // 初始化绘图窗口
Student students[3];
strcpy(students[0].name, "Alice");
students[0].age = 18;
strcpy(students[1].name, "Bob");
students[1].age = 19;
strcpy(students[2].name, "Charlie");
students[2].age = 20;
for (int i = 0; i < 3; i++) {
outtextxy(100, 100 + i * 20, students[i].name); // 输出姓名
char ageStr[5];
sprintf(ageStr, "%d", students[i].age); // 将年龄转换为字符串
outtextxy(200, 100 + i * 20, ageStr); // 输出年龄
}
getch();
closegraph(); // 关闭绘图窗口
return 0;
}
```
这样就可以使用`outtextxy`函数将结构数组中的内容输出到绘图窗口中了。
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