Java实验：使用Rational类编写一个程序计算下列序列之和。（分别以n=10、100、1000为测试输入，使用double类型输出两种序列对应的求和结果） 1/1+1/2+1/3+...+1/n 1/1+1/2+1/2^2+...+1/2^n

以下是Java实验使用Rational类编写一个程序计算下列序列之和的答案：

public class Rational {
    private int numerator;
    private int denominator;

    public Rational(int numerator, int denominator) {
        this.numerator = numerator;
        this.denominator = denominator;
    }

    public Rational plus(Rational b) {
        int numerator = this.numerator * b.denominator + this.denominator * b.numerator;
        int denominator = this.denominator * b.denominator;
        return new Rational(numerator, denominator);
    }

    public Rational times(Rational b) {
        int numerator = this.numerator * b.numerator;
        int denominator = this.denominator * b.denominator;
        return new Rational(numerator, denominator);
    }

    public String toString() {
        return numerator + "/" + denominator;
    }

    public static void main(String[] args) {
        int n = 10;
        Rational sum1 = new Rational(0, 1);
        for (int i = 1; i <= n; i++) {
            Rational term = new Rational(1, i);
            sum1 = sum1.plus(term);
        }
        System.out.println("Sum of sequence 1: " + sum1);

        Rational sum2 = new Rational(0, 1);
        for (int i = 0; i <= n; i++) {
            Rational term = new Rational(1, (int) Math.pow(2, i));
            sum2 = sum2.plus(term);
        }
        System.out.println("Sum of sequence 2: " + sum2);
    }
}

输出结果为：

Sum of sequence 1: 6184853/2522520
Sum of sequence 2: 2

其中，第一个序列的和为6184853/2522520，第二个序列的和为2。