s= "58City Yahoo5566, Kety Cat",print(re.match('(\w+) (\w+), (\w+) (\w+)', s).group(0))
时间: 2024-05-08 07:15:49 浏览: 63
SVN1.12.1汉化包.rar
There are a few errors in the code:
- The string s should be enclosed in quotes.
- The regular expression pattern is incorrect. It should match the string "58City Yahoo5566, Kety Cat", but the pattern provided doesn't match the comma and space between the two parts of the string.
- The group(0) method should return the entire matched string, not just the first group.
Here's a corrected version of the code:
```
import re
s = "58City Yahoo5566, Kety Cat"
print(re.match('(\w+)\s+(\w+),\s+(\w+)\s+(\w+)', s).group(0))
```
This will print the entire matched string "58City Yahoo5566, Kety Cat". The regular expression pattern includes four groups: the first word, the second word, the third word, and the fourth word. The \w+ pattern matches one or more word characters (letters, digits, or underscores), and \s+ matches one or more whitespace characters (spaces or tabs). The comma between the second and third words is matched literally with ,.
阅读全文