用C语言实现DNS域名解析通过UDP实现client端与localserver通信,请帮我实现client端
时间: 2024-03-11 12:44:29 浏览: 85
好的,以下是一个简单的用C语言实现DNS域名解析通过UDP实现client端与localserver通信的例子代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <arpa/inet.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#define SERVER "127.0.0.1" // localserver地址
#define BUFLEN 512 // 缓冲区长度
#define PORT 53 // DNS服务器端口号
void error(const char *msg) {
perror(msg);
exit(1);
}
int main(int argc, char **argv) {
struct sockaddr_in si_other; // server地址
int s, slen = sizeof(si_other), i;
char buf[BUFLEN];
if (argc < 2) {
printf("Usage: %s <hostname>\n", argv[0]);
return 0;
}
// 创建socket
if ((s = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP)) == -1) {
error("socket");
}
// 设置server地址
memset((char *) &si_other, 0, sizeof(si_other));
si_other.sin_family = AF_INET;
si_other.sin_port = htons(PORT);
if (inet_aton(SERVER, &si_other.sin_addr) == 0) {
fprintf(stderr, "inet_aton() failed\n");
exit(1);
}
// 构造DNS请求报文
char hostname[100];
strcpy(hostname, argv[1]);
for (i = 0; i < strlen(hostname); i++) {
if (hostname[i] == '.') {
hostname[i] = i - (i > 0 ? 1 : 0);
}
}
int len = strlen(hostname) + 1;
char dns_query[len + 16];
memset(dns_query, 0, len + 16);
dns_query[1] = 1;
dns_query[len + 15] = 1;
for (i = 0; i < len; i++) {
dns_query[i + 12] = hostname[i];
}
// 发送请求报文
if (sendto(s, dns_query, len + 16, 0, (struct sockaddr *) &si_other, slen) == -1) {
error("sendto");
}
// 接收响应报文
if (recvfrom(s, buf, BUFLEN, 0, (struct sockaddr *) &si_other, &slen) == -1) {
error("recvfrom");
}
// 解析响应报文
int answer_len = ntohs(*(unsigned short *)(buf + 6)) + 12;
char answer[answer_len];
memcpy(answer, buf, answer_len);
struct sockaddr_in addr;
memcpy(&addr.sin_addr, answer + answer_len - 4, 4);
printf("%s: %s\n", argv[1], inet_ntoa(addr.sin_addr));
close(s);
return 0;
}
```
该例子通过构造DNS请求报文,发送UDP数据包到localserver,接收localserver返回的响应报文,并解析出IP地址。
注意:该例子只适用于IPv4地址解析。
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