首页strlen.c:7:11: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int (*)(char *)’ [-Wformat=] printf("%d\n",my_strlenfun); ~^ ~~~~~~~~~~~~ strlen.c: At top level: strlen.c:10:5: error: conflicting types for ‘my_strlenfun’ int my_strlenfun(char const * ars) ^~~~~~~~~~~~ strlen.c:2:5: note: previous declaration of ‘my_strlenfun’ was here int my_strlenfun(char *); ^~~~~~~~~~~~是什么意思

strlen.c:7:11: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int ()(char )’ [-Wformat=] printf("%d\n",my_strlenfun); ~^ ~~~~~~ strlen.c: At top level: strlen.c:10:5: error: conflicting types for ‘my_strlenfun’ int my_strlenfun(char const * ars) ^~ strlen.c:2:5: note: previous declaration of ‘my_strlenfun’ was here int my_strlenfun(char *); ^~~~~~~~是什么意思

时间: 2023-07-03 20:33:09 浏览: 251

b64.c:Base64编码的代码

b64.c Base64编码/解码安装 $ clib install littlstar/b64.c 用法 # include < b64> 或者 # include < b64> # include < stdio> # include < string> # include < stdlib> # include " b64.h " int main ( void ) { unsigned char *str = " brian the monkey and bradley the kinkajou are friends " ; char *enc = b64_encode (str, strlen (str)); printf ( " %s \n " , enc); // YnJpYW4gdGhlIG1vbmtleSBhbm

这个错误提示意思是：文件 `strlen.c` 的第 7 行有一个警告，它告诉你 `printf` 函数期望的第二个参数是一个 `int` 类型，但是你传递给它的是一个函数指针，这是不匹配的。此外，第 10 行有一个错误，原因是 `my_strlenfun` 函数的类型与之前声明的不匹配。这意味着你在代码中有一个函数名冲突的问题。你需要检查并修复这些问题，以使代码可以正确编译和运行。

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