c语言写一个接口函数判断集合A是否属于集合B
时间: 2024-02-06 08:03:50 浏览: 62
好的,这个问题属于技术问题,我可以回答。您需要编写一个函数,可以判断集合A是否是集合B的子集。下面是一个示例代码:
```
#include <stdio.h>
int isSubset(int A[], int B[], int m, int n)
{
int i = 0, j = 0;
for (i = 0; i < n; i++)
{
for (j = 0; j < m; j++)
{
if(B[i] == A[j])
break;
}
/* If the above inner loop was
not broken at all then arr2[i]
is not present in arr1[] */
if (j == m)
return 0;
}
/* If we reach here then all
elements of arr2[] are present
in arr1[] */
return 1;
}
int main()
{
int A[] = {11, 1, 13, 21, 3, 7};
int B[] = {11, 3, 7, 1};
int m = sizeof(A)/sizeof(A[0]);
int n = sizeof(B)/sizeof(B[0]);
if(isSubset(A, B, m, n))
printf("A is a subset of B\n");
else
printf("A is not a subset of B\n");
}
```
您可以将集合A和集合B的元素作为数组传入isSubset函数中,并根据返回值判断集合A是否是集合B的子集。
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