python playwright 监听懒加载页面响应

如果你需要监听懒加载页面的响应，你可以使用 Playwright 的 `page.waitForEvent('response')` 方法来等待页面响应。

下面是一个示例代码，演示如何在 Python Playwright 中监听懒加载页面的响应：

from playwright.sync_api import Playwright, sync_playwright

def main(playwright: Playwright) -> None:
    browser = playwright.chromium.launch()
    page = browser.new_page()

    # 监听页面响应
    def handle_response(response):
        print(f"响应 URL: {response.url}")
        print(f"响应状态码: {response.status}")

    # 等待页面中的某个元素出现
    page.wait_for_selector("#lazy-loaded-element")

    # 等待页面响应
    response = page.wait_for_event("response")

    # 处理页面响应
    handle_response(response)

    browser.close()

with sync_playwright() as playwright:
    main(playwright)

在上面的示例中，我们首先使用 `page.wait_for_selector(selector)` 方法等待页面中的某个元素出现，以触发懒加载。然后，我们使用 `page.wait_for_event(event)` 方法等待页面收到响应。最后，我们在监听器中处理响应。