com.kingsware.uiautomator.automator.Selector@15efac; boundsInParent: Rect(0, 0 - 729, 68); boundsInScreen: Rect(228, 471 - 957, 539); packageName: com.tencent.mm; className: android.view.View; text: 微信发送测试群; contentDescription: null; viewId: com.tencent.mm:id/hg4; checkable: false; checked: false; focusable: false; focused: false; selected: false; clickable: false; longClickable: false; enabled: true; password: false; scrollable: false; [ACTION_SELECT, ACTION_CLEAR_SELECTION, ACTION_ACCESSIBILITY_FOCUS, ACTION_SHOW_ON_SCREEN]，请写一个正则表达式把boundsInScreen:Rect()里面的数据提取出来

好的，这是一个提取矩形框坐标的正则表达式：`boundsInScreen:\s*Rect\((\d+),\s*(\d+)\s*s*(\d+),\s*(\d)`。使用时，可以先将文本中的换行符去掉，并将其中的矩形坐标数据提取出来。例如，在Python中可以这样使用：

import re

text = "com.kingsware.uiautomator.automator.Selector@15efac; boundsInParent: Rect(0, 0 - 729, 68); boundsInScreen: Rect(228, 471 - 957, 539); packageName: com.tencent.mm; className: android.view.View; text: 微信发送测试群; contentDescription: null; viewId: com.tencent.mm:id/hg4; checkable: false; checked: false; focusable: false; focused: false; selected: false; clickable: false; longClickable: false; enabled: true; password: false; scrollable: false; [ACTION_SELECT, ACTION_CLEAR_SELECTION, ACTION_ACCESSIBILITY_FOCUS, ACTION_SHOW_ON_SCREEN]"
match = re.search(r'boundsInScreen:\s*Rect\((\d+),\s*(\d+)\s*-\s*(\d+),\s*(\d+)\)', text.replace('\n', ' '))
if match:
    x1, y1, x2, y2 = match.groups()
    print("矩形框坐标：({}, {})-({}, {})".format(x1, y1, x2, y2))
else:
    print("未找到矩形框坐标")

输出结果为：`矩形框坐标：(228, 471)-(957, 539)`。