用Java定义一个二维数组，从键盘输入一个矩阵的值，对矩阵进行转置，输出转置后的矩阵。并求出原矩阵中的最大值和最小值，输出其所在的行号和列号。（不要使用方法）

好的，以下是解答：

import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("请输入矩阵的行数和列数（用空格隔开）：");
int row = scanner.nextInt();
int column = scanner.nextInt();
int[][] matrix = new int[row][column];
System.out.println("请输入矩阵的值：");
for (int i = 0; i < row; i++) {
for (int j = 0; j < column; j++) {
matrix[i][j] = scanner.nextInt();
}
}
System.out.println("\n原矩阵：");
for (int i = 0; i < row; i++) {
for (int j = 0; j < column; j++) {
System.out.print(matrix[i][j] + " ");
}
System.out.println();
}
System.out.println("\n转置后的矩阵：");
for (int i = 0; i < column; i++) {
for (int j = 0; j < row; j++) {
System.out.print(matrix[j][i] + " ");
}
System.out.println();
}
int max = Integer.MIN_VALUE;
int min = Integer.MAX_VALUE;
int maxRow = 0, maxColumn = 0, minRow = 0, minColumn = 0;
for (int i = 0; i < row; i++) {
for (int j = 0; j < column; j++) {
if (matrix[i][j] > max) {
max = matrix[i][j];
maxRow = i+1;
maxColumn = j+1;
}
if (matrix[i][j] < min) {
min = matrix[i][j];
minRow = i+1;
minColumn = j+1;
}
}
}
System.out.println("\n最大值：" + max + "，所在行：" + maxRow + "，所在列：" + maxColumn);
System.out.println("最小值：" + min + "，所在行：" + minRow + "，所在列：" + minColumn);
}
}

希望解答能够帮到你，如果你还有其他问题，可以继续问我。