现有weather.json文件，内容如下： [ {"temp":"20℃/30℃","weather":"晴转多云","city":"上海","pm":"2.5","wind":"1级"}, {"temp":"15℃/24℃","weather":"晴","city":"北京","pm":"3","wind":"3级"}, {"temp":"26℃/32℃","weather":"多云","city":"广州","pm":"4","wind":"2级"} ] ，请封装jsonParse方法解析Json数据。 public List<Weather> jsonParse(String json){ }

好的，您的问题已经记录下来了，我会根据您的要求进行回答。

关于您的问题，下面是封装jsonParse方法解析Json数据的代码：

import com.alibaba.fastjson.JSONArray;
import com.alibaba.fastjson.JSONObject;
import java.util.ArrayList;
import java.util.List;

public class Weather {
    private String temp;
    private String weather;
    private String city;
    private String pm;
    private String wind;

    public Weather(String temp, String weather, String city, String pm, String wind) {
        this.temp = temp;
        this.weather = weather;
        this.city = city;
        this.pm = pm;
        this.wind = wind;
    }

    // getters and setters

    public static List<Weather> jsonParse(String json) {
        List<Weather> weatherList = new ArrayList<>();
        JSONArray jsonArray = JSONArray.parseArray(json);
        for (int i = 0; i < jsonArray.size(); i++) {
            JSONObject jsonObject = jsonArray.getJSONObject(i);
            String temp = jsonObject.getString("temp");
            String weather = jsonObject.getString("weather");
            String city = jsonObject.getString("city");
            String pm = jsonObject.getString("pm");
            String wind = jsonObject.getString("wind");
            Weather weatherObj = new Weather(temp, weather, city, pm, wind);
            weatherList.add(weatherObj);
        }
        return weatherList;
    }
}

这段代码中，我们使用了FastJson这个第三方库来解析Json数据。在jsonParse方法中，我们首先将Json字符串转化为JSONArray对象，然后遍历JSONArray的每一个元素，将JSONObject中对应的属性值赋值给对应的属性，最后将生成的Weather对象加入到List中，并返回List。

希望这个解答能够解决您的问题！