一个人每工作3天就要休息两天，假设在工作日阶段每天进步0.01；不工作时退步0.001的Python测试代码

progress_per_day = 0.01
regress_per_day = 0.001

days_worked = 0
days_rest = 0
total_progress = 0

for i in range(365):
    if days_worked < 3:
        total_progress += progress_per_day
        days_worked += 1
    else:
        total_progress -= regress_per_day
        days_rest += 1
        if days_rest == 2:
            days_worked = 0
            days_rest = 0
            
print("Total progress in a year:", total_progress)

这段代码模拟了一年中每工作3天就要休息两天的情况，每个工作日进步0.01，不工作时退步0.001，最后输出一年总进步。