python3根据所学知识，设计Get Area函数，要求该函数能计算矩形， 三角形，圆形，梯形的面积

在Python中，你可以设计一个通用的`GetArea`函数，它接受形状的类型以及相应的属性作为输入参数，然后根据每个形状的特定公式来计算面积。这里是一个简单的示例：

import math

class Shape:
    def __init__(self, name, *args):
        self.name = name
        self.args = args

    def get_area(self):
        raise NotImplementedError("Subclass must implement this method")

class Rectangle(Shape):
    def __init__(self, length, width):
        super().__init__("Rectangle", length, width)
        
    def get_area(self):
        return self.args[0] * self.args[1]

class Triangle(Shape):
    def __init__(self, base, height):
        super().__init__("Triangle", base, height)
        
    def get_area(self):
        return 0.5 * self.args[0] * self.args[1]

class Circle(Shape):
    def __init__(self, radius):
        super().__init__("Circle", radius)
        
    def get_area(self):
        return math.pi * (self.args[0]**2)

class Trapezoid(Shape):
    def __init__(self, a, b, height):
        super().__init__("Trapezoid", a, b, height)
        
    def get_area(self):
        return 0.5 * (self.args[0] + self.args[1]) * self.args[2]

def GetArea(shape_type, *shape_params):
    shapes = {
        "Rectangle": Rectangle,
        "Triangle": Triangle,
        "Circle": Circle,
        "Trapezoid": Trapezoid,
    }
    
    if shape_type in shapes:
        return shapes[shape_type](*shape_params).get_area()
    else:
        print(f"Unsupported shape type: {shape_type}")

# 使用示例
area_rectangle = GetArea("Rectangle", 4, 6)  # 面积为24
area_triangle = GetArea("Triangle", 3, 4)   # 面积为6
area_circle = GetArea("Circle", 5)         # 面积约为78.54
area_trapezoid = GetArea("Trapezoid", 3, 5, 4)  # 面积为16