C语言实现加减乘除随机出题错题重做功能

好的，这是一个比较复杂的问题，我会尽可能详细地回答。首先，为了实现加减乘除的随机出题，我们需要使用随机数生成器来生成两个操作数和一个运算符。C语言中可以使用rand()函数来生成随机数，但是需要先调用srand()函数设置随机数种子。

下面是一个示例代码，可以随机生成包含加减乘除四种运算的数学题目：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    int operand1, operand2, result;
    char operator;
    srand(time(NULL)); // 设置随机数种子为当前时间

    // 生成随机数和运算符
    operand1 = rand() % 100;
    operand2 = rand() % 100;
    switch (rand() % 4) {
        case 0: operator = '+'; result = operand1 + operand2; break;
        case 1: operator = '-'; result = operand1 - operand2; break;
        case 2: operator = '*'; result = operand1 * operand2; break;
        case 3: operator = '/'; result = operand1 / operand2; break;
    }

    // 输出题目
    printf("%d %c %d = ?\n", operand1, operator, operand2);

    return 0;
}

接下来是实现错题重做功能的部分。我们可以使用一个数组来保存错题的题目和答案，然后在程序结束之前输出这些错题，让用户重新回答。

下面是一个简单的示例代码，可以实现记录错题和重做错题的功能：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define MAX_WRONG_ANSWERS 10

struct Question {
    int operand1, operand2, answer;
    char operator;
};

int main() {
    int num_wrong_answers = 0;
    struct Question wrong_answers[MAX_WRONG_ANSWERS];
    srand(time(NULL)); // 设置随机数种子为当前时间

    // 循环出题
    while (num_wrong_answers < MAX_WRONG_ANSWERS) {
        int operand1 = rand() % 100;
        int operand2 = rand() % 100;
        int answer;
        char operator;
        switch (rand() % 4) {
            case 0: operator = '+'; answer = operand1 + operand2; break;
            case 1: operator = '-'; answer = operand1 - operand2; break;
            case 2: operator = '*'; answer = operand1 * operand2; break;
            case 3: operator = '/'; answer = operand1 / operand2; break;
        }

        // 输出题目
        printf("%d %c %d = ?\n", operand1, operator, operand2);

        // 获取用户输入
        int user_answer;
        scanf("%d", &user_answer);

        // 检查用户答案是否正确，如果不正确则记录下来
        if (user_answer != answer) {
            struct Question wrong_answer = {operand1, operand2, answer, operator};
            wrong_answers[num_wrong_answers++] = wrong_answer;
            printf("Wrong answer. The correct answer is %d.\n", answer);
        } else {
            printf("Correct!\n");
        }
    }

    // 输出错题并让用户重做
    printf("You have answered %d questions incorrectly. Here are the wrong answers:\n", num_wrong_answers);
    for (int i = 0; i < num_wrong_answers; i++) {
        printf("%d %c %d = %d\n", wrong_answers[i].operand1, wrong_answers[i].operator, wrong_answers[i].operand2, wrong_answers[i].answer);
        printf("Please answer again: ");
        int user_answer;
        scanf("%d", &user_answer);
        if (user_answer != wrong_answers[i].answer) {
            printf("Wrong answer again. The correct answer is %d.\n", wrong_answers[i].answer);
        } else {
            printf("Correct!\n");
        }
    }

    return 0;
}

以上是一个简单的实现，你可以根据自己的需要进行修改和扩展。