es排除neme不等于"已解决", "已关闭", "关闭", "已处理", "已完成", "已完结", "已结束"
时间: 2023-07-24 22:14:27 浏览: 66
可以使用以下查询条件来排除neme不等于指定的值:
`neme:(NOT "已解决" AND NOT "已关闭" AND NOT "关闭" AND NOT "已处理" AND NOT "已完成" AND NOT "已完结" AND NOT "已结束")`
这将排除所有neme字段等于"已解决"、"已关闭"、"关闭"、"已处理"、"已完成"、"已完结"和"已结束"的结果。
相关问题
class demo{ demo &hh(string name) { cout<<neme<<endl; return *this; } }; int main() { dem obj; obj.hh("wjl").hh("hello"); }
你在这段代码中定义了一个名为`demo`的类,该类具有一个名为`hh`的成员函数。`hh`函数接受一个字符串参数`name`,并输出该字符串。然后它返回一个指向当前对象的引用`*this`。
在`main`函数中,你创建了一个名为`obj`的`demo`类对象,并连续调用了两次`hh`函数。首先,你将字符串"wjl"传递给第一个调用,并将结果链式调用传递给第二次调用,传递了字符串"hello"。
但是,这段代码存在一些错误。首先,在类定义中,你使用了`cout<<neme<<endl;`来输出参数`name`,而不是正确的`cout<<name<<endl;`。此外,在`main`函数中,你声明了一个名为`dem`的类对象,而不是正确的`demo`。
正确的代码示例如下:
```cpp
#include <iostream>
using namespace std;
class demo {
public:
demo& hh(string name) {
cout << name << endl;
return *this;
}
};
int main() {
demo obj;
obj.hh("wjl").hh("hello");
return 0;
}
```
这样,代码就能够正确输出字符串"wjl"和"hello"。
1) Student类: 属性id, neme,specialty,avggrade,方法outPut ()输出所有属性的信息。 方法outMaxAvgstu()输出专业第一名学生的信息。 (2) StudentTest类:创建数组,数组的类型为 Student类,创建5个的元素,调用上述的两个方法
答案:
Sure, I can help you with this question! Here is the code for the Student class:
```
public class Student {
private int id;
private String name;
private String specialty;
private double avgGrade;
public Student(int id, String name, String specialty, double avgGrade) {
this.id = id;
this.name = name;
this.specialty = specialty;
this.avgGrade = avgGrade;
}
public void outPut() {
System.out.println("Student Information:");
System.out.println("id: " + id);
System.out.println("name: " + name);
System.out.println("specialty: " + specialty);
System.out.println("avgGrade: " + avgGrade);
}
public static void outMaxAvgstu(Student[] students) {
double maxAvgGrade = -1;
int maxAvgGradeIndex = -1;
for (int i = 0; i < students.length; i++) {
if (students[i].avgGrade > maxAvgGrade) {
maxAvgGrade = students[i].avgGrade;
maxAvgGradeIndex = i;
}
}
System.out.println("The student with the highest average grade is:");
students[maxAvgGradeIndex].outPut();
}
}
```
And here is the code for the StudentTest class:
```
public class StudentTest {
public static void main(String[] args) {
Student[] students = new Student[5];
students[0] = new Student(1, "Alice", "Computer Science", 3.9);
students[1] = new Student(2, "Bob", "Electrical Engineering", 3.8);
students[2] = new Student(3, "Charlie", "Mechanical Engineering", 3.7);
students[3] = new Student(4, "David", "Civil Engineering", 3.6);
students[4] = new Student(5, "Emily", "Chemical Engineering", 3.5);
System.out.println("All students:");
for (Student student : students) {
student.outPut();
System.out.println();
}
Student.outMaxAvgstu(students);
}
}
```
Hope this helps!