str_contains(): Argument #1 ($haystack) must be of type string, int given

此错误提示在PHP中表示当你在使用`str_contains()`函数时，传递给它的第一个参数（$haystack）不是一个字符串类型，而是整数类型（int）。`str_contains()`函数用于查找字符串中是否包含特定的子串，所以它期望接收一个字符串作为搜索的目标。

修复这个问题，你需要确保传递给`str_contains()`的参数是一个字符串。如果 `$haystack` 是从别处获取的，可能需要先将其转换为字符串。例如：

$string = (string)$haystack; // 将整数转换为字符串
$result = stripos($string, $search); // 使用stripos替代，因为它可以接受整数作为起始位置
if ($result !== false) {
    // 字符串存在
} else {
    // 字符串不存在
}

或者使用 Laravel 中的`Str::contains()`方法，它会自动处理非字符串的情况：

if (Str::contains((string)$haystack, $search)) {
    // ...
}

相关问题

str() argument 2 must be str, not numpy.int32

This error occurs when you try to concatenate a string with an integer using the str() function. The argument passed to the function must be a string, but in this case, it is a numpy.int32 integer.

To fix this error, you can convert the integer to a string using the str() function before concatenating it with the other string. Here's an example:

import numpy as np

a = np.int32(10)
b = "The value of a is: " + str(a)
print(b)

Output:

The value of a is: 10

TypeError: First argument must be a string, Buffer, ArrayBuffer, Array, or a

This error occurs when the first argument passed to a function must be one of the mentioned data types, but it is not.

To resolve this error, you should check the argument being passed to the function and make sure it is of the correct data type. For example, if the function expects a string as the first argument, you can use the `typeof` operator to check if the argument is a string before passing it to the function:

function myFunction(str) {
  if (typeof str !== 'string') {
    throw new TypeError('First argument must be a string');
  }
  // rest of the function code here
}

This will throw an error if the first argument is not a string, allowing you to catch the error and fix it.