有如下列表num1=['first','second','third','fourth','fifth'],要求分别利用循环和列表推导式得到其对应的简写列表['1st', '2nd', '3rd', '4th', '5th'];
时间: 2023-10-23 11:25:52 浏览: 73
利用循环的方法:
```python
num1 = ['first','second','third','fourth','fifth']
short_list = []
for num in num1:
if num == 'first':
short_list.append('1st')
elif num == 'second':
short_list.append('2nd')
elif num == 'third':
short_list.append('3rd')
else:
short_list.append(num[:1] + 'th')
print(short_list)
```
利用列表推导式的方法:
```python
num1 = ['first','second','third','fourth','fifth']
short_list = ['1st' if num=='first' else '2nd' if num=='second' else '3rd' if num=='third' else num[:1]+'th' for num in num1]
print(short_list)
```
相关问题
pyhton有如下列表num1=['first','second','third','fourth','fifth'],要求分别利用循环和列表推导式得到其对应的简写列表['1st', '2nd', '3rd', '4th', '5th'];
利用循环可以通过遍历列表元素并进行相应的处理得到简写列表:
```python
num1 = ['first', 'second', 'third', 'fourth', 'fifth']
short_list = []
for num in num1:
if num == 'first':
short_list.append('1st')
elif num == 'second':
short_list.append('2nd')
elif num == 'third':
short_list.append('3rd')
else:
short_list.append(num[0] + 'th')
print(short_list)
```
利用列表推导式可以更简洁地得到简写列表:
```python
num1 = ['first', 'second', 'third', 'fourth', 'fifth']
short_list = ['1st' if num == 'first' else '2nd' if num == 'second' else '3rd' if num == 'third' else num[0] + 'th' for num in num1]
print(short_list)
```
program_list = [debug, first, second, third, fourth, fifth, sixth, seventh, eighth, test]
好的,我已经记录下了您的问题。关于您提到的程序列表,这是一个包含了十个程序的列表,分别为:debug、first、second、third、fourth、fifth、sixth、seventh、eighth和test。需要注意的是,这个列表中的每个程序都需要被正确地定义和实现,才能确保程序的正常运行。