用c++写一个贪吃蛇代码

好的，我可以回答这个问题。以下是一个简单的贪吃蛇代码示例：

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <time.h>

#define ROW 20
#define COL 30

int snake[ROW*COL][2];
int food[2];
int len = 3;
int score = ;

void init();
void draw();
void update();
void generate_food();

int main()
{
    init();
    while (1)
    {
        draw();
        update();
        if (snake[][] <  || snake[][] >= ROW || snake[][1] <  || snake[][1] >= COL)
        {
            printf("Game over! Your score is %d.\n", score);
            break;
        }
        for (int i = 1; i < len; i++)
        {
            if (snake[][] == snake[i][] && snake[][1] == snake[i][1])
            {
                printf("Game over! Your score is %d.\n", score);
                return ;
            }
        }
        if (snake[][] == food[] && snake[][1] == food[1])
        {
            len++;
            score++;
            generate_food();
        }
        Sleep(100);
    }
    return ;
}

void init()
{
    srand((unsigned)time(NULL));
    snake[][] = rand() % ROW;
    snake[][1] = rand() % COL;
    for (int i = 1; i < len; i++)
    {
        snake[i][] = snake[i - 1][] + 1;
        snake[i][1] = snake[i - 1][1];
    }
    generate_food();
}

void draw()
{
    system("cls");
    for (int i = ; i < ROW; i++)
    {
        for (int j = ; j < COL; j++)
        {
            if (i == snake[][] && j == snake[][1])
            {
                printf("O");
            }
            else if (i == food[] && j == food[1])
            {
                printf("*");
            }
            else
            {
                int flag = ;
                for (int k = 1; k < len; k++)
                {
                    if (i == snake[k][] && j == snake[k][1])
                    {
                        printf("o");
                        flag = 1;
                        break;
                    }
                }
                if (!flag)
                {
                    printf(" ");
                }
            }
        }
        printf("\n");
    }
    printf("Score: %d\n", score);
}

void update()
{
    if (_kbhit())
    {
        char c = _getch();
        switch (c)
        {
        case 'w':
            for (int i = len - 1; i > ; i--)
            {
                snake[i][] = snake[i - 1][];
                snake[i][1] = snake[i - 1][1];
            }
            snake[][]--;
            break;
        case 's':
            for (int i = len - 1; i > ; i--)
            {
                snake[i][] = snake[i - 1][];
                snake[i][1] = snake[i - 1][1];
            }
            snake[][]++;
            break;
        case 'a':
            for (int i = len - 1; i > ; i--)
            {
                snake[i][] = snake[i - 1][];
                snake[i][1] = snake[i - 1][1];
            }
            snake[][1]--;
            break;
        case 'd':
            for (int i = len - 1; i > ; i--)
            {
                snake[i][] = snake[i - 1][];
                snake[i][1] = snake[i - 1][1];
            }
            snake[][1]++;
            break;
        default:
            break;
        }
    }
    else
    {
        for (int i = len - 1; i > ; i--)
        {
            snake[i][] = snake[i - 1][];
            snake[i][1] = snake[i - 1][1];
        }
        snake[][1]++;
    }
}

void generate_food()
{
    int flag = ;
    while (!flag)
    {
        food[] = rand() % ROW;
        food[1] = rand() % COL;
        flag = 1;
        for (int i = ; i < len; i++)
        {
            if (food[] == snake[i][] && food[1] == snake[i][1])
            {
                flag = ;
                break;
            }
        }
    }
}

这个代码使用了 Windows 系统的 conio.h 库，所以在 Linux 或 Mac 上可能无法编译运行。如果需要在 Linux 或 Mac 上运行，需要使用相应的替代库来实现键盘输入和清屏等功能。