Java1. 应用ArrayList实现某专业所有学生的成绩管理，要求构建学生（Student）类和成绩（AcademicRecord）类等，能够对不同年级的学生按总成绩排序并输出. Student(name,studID,major,grade, ArrayList< AcademicRecord > scores); AcademicRecord(studID,courseID,score) 要求学生类实现Comparable接口，排序按年级、成绩排； 并实现学生相同的判断（重写equals），当学生姓名和学号一样时，则学生相同。

好的，这是一个非常典型的Java面向对象编程问题，需要你构建两个类：Student和AcademicRecord，并且让Student类实现Comparable接口，重写equals方法。下面是一个基本的实现：

import java.util.ArrayList;
import java.util.Collections;

public class Student implements Comparable<Student> {
    private String name;
    private String studID;
    private String major;
    private int grade;
    private ArrayList<AcademicRecord> scores;

    public Student(String name, String studID, String major, int grade, ArrayList<AcademicRecord> scores) {
        this.name = name;
        this.studID = studID;
        this.major = major;
        this.grade = grade;
        this.scores = scores;
    }

    public String getName() {
        return name;
    }

    public String getStudID() {
        return studID;
    }

    public String getMajor() {
        return major;
    }

    public int getGrade() {
        return grade;
    }

    public ArrayList<AcademicRecord> getScores() {
        return scores;
    }

    public void setName(String name) {
        this.name = name;
    }

    public void setStudID(String studID) {
        this.studID = studID;
    }

    public void setMajor(String major) {
        this.major = major;
    }

    public void setGrade(int grade) {
        this.grade = grade;
    }

    public void setScores(ArrayList<AcademicRecord> scores) {
        this.scores = scores;
    }

    // 计算总成绩
    public int getTotalScore() {
        int totalScore = 0;
        for (AcademicRecord record : scores) {
            totalScore += record.getScore();
        }
        return totalScore;
    }

    // 实现Comparable接口，按年级、成绩排序
    @Override
    public int compareTo(Student o) {
        if (this.grade != o.grade) {
            return this.grade - o.grade;
        } else {
            return o.getTotalScore() - this.getTotalScore();
        }
    }

    // 重写equals方法，当姓名和学号一致时则相同
    @Override
    public boolean equals(Object obj) {
        if (this == obj) {
            return true;
        }
        if (obj instanceof Student) {
            Student s = (Student) obj;
            if (this.name.equals(s.name) && this.studID.equals(s.studID)) {
                return true;
            }
        }
        return false;
    }

    public static void main(String[] args) {
        // 构造学生和成绩数据
        ArrayList<AcademicRecord> scores1 = new ArrayList<>();
        scores1.add(new AcademicRecord("1001", "语文", 80));
        scores1.add(new AcademicRecord("1001", "数学", 90));
        scores1.add(new AcademicRecord("1001", "英语", 85));
        Student s1 = new Student("张三", "1001", "计算机科学", 3, scores1);

        ArrayList<AcademicRecord> scores2 = new ArrayList<>();
        scores2.add(new AcademicRecord("1002", "语文", 75));
        scores2.add(new AcademicRecord("1002", "数学", 95));
        scores2.add(new AcademicRecord("1002", "英语", 80));
        Student s2 = new Student("李四", "1002", "计算机科学", 2, scores2);

        ArrayList<AcademicRecord> scores3 = new ArrayList<>();
        scores3.add(new AcademicRecord("1003", "语文", 85));
        scores3.add(new AcademicRecord("1003", "数学", 70));
        scores3.add(new AcademicRecord("1003", "英语", 90));
        Student s3 = new Student("王五", "1003", "计算机科学", 4, scores3);

        // 构造学生列表
        ArrayList<Student> students = new ArrayList<>();
        students.add(s1);
        students.add(s2);
        students.add(s3);

        // 对学生列表按总成绩排序并输出
        Collections.sort(students);
        for (Student student : students) {
            System.out.println(student.getName() + " " + student.getStudID() + " " + student.getMajor() + " " + student.getGrade() + " " + student.getTotalScore());
        }
    }
}

class AcademicRecord {
    private String studID;
    private String courseID;
    private int score;

    public AcademicRecord(String studID, String courseID, int score) {
        this.studID = studID;
        this.courseID = courseID;
        this.score = score;
    }

    public String getStudID() {
        return studID;
    }

    public String getCourseID() {
        return courseID;
    }

    public int getScore() {
        return score;
    }

    public void setStudID(String studID) {
        this.studID = studID;
    }

    public void setCourseID(String courseID) {
        this.courseID = courseID;
    }

    public void setScore(int score) {
        this.score = score;
    }
}

在这个例子中，我们构造了两个类：Student和AcademicRecord。Student类包含了姓名、学号、专业、年级和成绩列表等属性，其中成绩列表是一个ArrayList类型的数据结构，存储了该学生的各门课程的成绩。Student类实现了Comparable接口，并重写了compareTo方法，实现了按年级、成绩排序的功能。另外，我们还重写了equals方法，实现了当姓名和学号一致时则相同的功能。

我们在main方法中构造了三个学生对象，并将它们放入一个ArrayList中，然后使用Collections.sort方法对这个ArrayList进行排序，排序的依据是按照学生的年级和总成绩。最后，我们遍历这个ArrayList，输出排序后的学生信息。