手术排程算法具体代码演示
时间: 2023-07-03 14:07:58 浏览: 72
手术排程算法是一种复杂的算法,需要考虑到多个因素,如手术时长、手术室可用性、医生和护士的可用性等等。以下是一个简单的手术排程算法的代码演示,供参考:
```
class Surgery:
def __init__(self, name, surgeon, duration):
self.name = name
self.surgeon = surgeon
self.duration = duration
class Schedule:
def __init__(self, surgeries):
self.surgeries = surgeries
self.rooms = ['Room 1', 'Room 2', 'Room 3', 'Room 4']
self.schedule = {}
def schedule_surgeries(self):
surgeons = set([surgery.surgeon for surgery in self.surgeries])
for surgeon in surgeons:
surgeon_surgeries = [surgery for surgery in self.surgeries if surgery.surgeon == surgeon]
sorted_surgeries = sorted(surgeon_surgeries, key=lambda x: x.duration)
for surgery in sorted_surgeries:
scheduled = False
for room in self.rooms:
if not self.is_room_occupied(room, surgery.duration):
self.schedule[surgery.name] = (surgeon, room)
scheduled = True
break
if not scheduled:
print(f'Unable to schedule surgery {surgery.name} for surgeon {surgeon}')
def is_room_occupied(self, room, duration):
for surgery, (surgeon, scheduled_room) in self.schedule.items():
if scheduled_room == room:
surgery_duration = [s.duration for s in self.surgeries if s.name == surgery][0]
if duration + surgery_duration > 8:
return True
return False
if __name__ == '__main__':
surgeries = [Surgery('Surgery 1', 'Surgeon A', 2),
Surgery('Surgery 2', 'Surgeon A', 3),
Surgery('Surgery 3', 'Surgeon B', 1),
Surgery('Surgery 4', 'Surgeon B', 4)]
schedule = Schedule(surgeries)
schedule.schedule_surgeries()
print(schedule.schedule)
```
在上面的代码中,我们首先定义了两个类:Surgery 和 Schedule。Surgery 类表示一台手术,包括手术名称、主刀医生和手术时长。Schedule 类表示手术排程,包括需要排的一组手术和可用的手术室。我们的算法就是通过对这些手术进行排序和分配,找到最优的排程方案。
在 schedule_surgeries 方法中,我们首先遍历所有的医生,对每个医生的手术按照时长进行排序。然后依次尝试将每台手术分配到可用的手术室中。如果当前手术室已经被占用,则需要检查该手术室中已经排好的手术是否会与当前手术时间冲突(即是否超过了8个小时的时间限制)。
最终,我们得到了一个手术排程的字典,其中键是手术名称,值是一个元组,表示主刀医生和手术室。这个排程方案可能并不是最优的,但是可以满足手术室和医生的可用性限制。