原始宏有四个参数

非常抱歉，我的回答有误。原始宏有四个参数，而不是三个参数。在这种情况下，将逆时针旋转90度的宏修改如下：

#define ROTATE_BITMAP(pattern_array, width, height, row_size) \
    for (int i = 0; i < (width / 2); i++) { \
        for (int j = 0; j < height; j++) { \
            uint8_t temp = PATTERN_BITMAP(pattern_array, width, j, i); \
            *((uint8_t *)pattern_array + width * j + i/8) &= ~(1 << (7-(i%8))); \
            *((uint8_t *)pattern_array + width * j + i/8) |= (PATTERN_BITMAP(pattern_array, width, j, width-i-1) << (7-(i%8))); \
            *((uint8_t *)pattern_array + width * j + (width-i-1)/8) &= ~(1 << (7-((width-i-1)%8))); \
            *((uint8_t *)pattern_array + width * j + (width-i-1)/8) |= (temp << (7-((width-i-1)%8))); \
        } \
    } \
    for (int i = 0; i < width; i++) { \
        for (int j = i+1; j < height; j++) { \
            uint8_t temp = PATTERN_BITMAP(pattern_array, width, i, j); \
            *((uint8_t *)pattern_array + width * i + j/8) &= ~(1 << (7-(j%8))); \
            *((uint8_t *)pattern_array + width * i + j/8) |= (PATTERN_BITMAP(pattern_array, width, j, i) << (7-(j%8))); \
            *((uint8_t *)pattern_array + width * j + i/8) &= ~(1 << (7-(i%8))); \
            *((uint8_t *)pattern_array + width * j + i/8) |= (temp << (7-(i%8))); \
        } \
    } \
    for (int i = 0; i < height; i++) { \
        for (int j = width; j > row_size; j--) { \
            uint8_t temp = PATTERN_BITMAP(pattern_array, width, i, j-1); \
            *((uint8_t *)pattern_array + width * i + j/8 - 1) &= ~(1 << (7-((j-1)%8))); \
            *((uint8_t *)pattern_array + width * i + j/8 - 1) |= (temp << (7-((j-1)%8))); \
        } \
    }

其中，pattern_array是要旋转的位图的数组指针，width表示每一行的字节数，height表示位图的行数，row_size表示位图每一行实际需要的字节数。该宏会将位图逆时针旋转90度，并将多余的列按顺序拼接到列的后面，最终结果会保存在原始的位图中。