c语言全排列问题伪代码及流程图

伪代码：

void permute(char* str, int start, int end)
{
    if(start == end)
    {
        print(str);
    }
    else
    {
        for(int i = start; i <= end; i++)
        {
            swap(str[start], str[i]);
            permute(str, start + 1, end);
            swap(str[start], str[i]);
        }
    }
}

流程图：

start permute(str, start, end)
|
|__ if start == end
|       print str
|
|__ else
|       for i = start to end
|           swap str[start], str[i]
|           permute(str, start + 1, end)
|           swap str[start], str[i]
|           
end