invalid literal for int() with base 10: '1 2'
时间: 2023-10-16 15:27:47 浏览: 136
This error message occurs when you try to convert a string that is not a valid integer to an integer using the int() function. In this case, the string '1 2' contains a space between the numbers, which is not allowed in an integer.
To fix this error, you can remove the space between the numbers or split the string into separate substrings and convert each substring to an integer separately. For example:
```
# Removing space between numbers
my_string = '12'
my_int = int(my_string)
# Splitting string and converting to integers
my_string = '1 2'
my_ints = [int(x) for x in my_string.split()]
```
相关问题
ValueError: invalid literal for intO with base 10:2005.03.07' on line 151是什么意思
这个错误提示`ValueError: invalid literal for int() with base 10: '2005.03.07'`是在Python中发生的,当你试图将一个字符串转换为整数(int类型)时出现了问题。在这个例子中,`2005.03.07`不是一个有效的十进制数字,因为`.03.07`这部分不是整数值。
错误发生的具体位置是第151行。通常,`int()`函数用于解析文本表示的整数,但这里它遇到了包含日期或小数点的格式,这超出了它的预期范围。如果你确实想把这样的日期字符串转换成整数,可能需要先正确地解析它,例如使用`datetime`模块将其转换为日期对象,然后再提取年份等信息。
纠正这个问题的方法取决于你的具体需求。如果你希望保留年月日信息,而不是简单地转换为整数,那么就不需要处理这个错误。如果需要的是单独的年份值,你可以尝试按照"YYYY.MM.DD"的格式分割字符串,然后取第一个部分作为年份:
```python
date_str = "2005.03.07"
year = int(date_str.split('.')[0])
```
ValueError: invalid literal for int() with base 10: 1
这个错误是由于将非数字的字符串转换为整数时引起的。在这个特定的例子中,错误是因为尝试将字符串"balabala"转换为整数时出现的。要解决这个问题,你需要确保你传递给int()函数的参数是一个有效的数字字符串。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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