java8写一个将List<A>与List<B>中多个字段的值进行匹配，匹配一致的List<A>与List<B>分别出力

假设List<A>中有属性a1、a2，List<B>中有属性b1、b2，要匹配a1与b1以及a2与b2是否一致，若一致则将相应的List<A>与List<B>分别输出。

代码如下：

import java.util.ArrayList;
import java.util.List;

public class MatchList {
    public static void main(String[] args) {
        List<A> aList = new ArrayList<>();
        aList.add(new A("a1", 1));
        aList.add(new A("a2", 2));
        aList.add(new A("a3", 3));

        List<B> bList = new ArrayList<>();
        bList.add(new B("b2", 2));
        bList.add(new B("b1", 1));
        bList.add(new B("b4", 4));

        List<A> matchedAList = new ArrayList<>();
        List<B> matchedBList = new ArrayList<>();

        for (A a : aList) {
            for (B b : bList) {
                if (a.getA1().equals(b.getB1()) && a.getA2() == b.getB2()) {
                    matchedAList.add(a);
                    matchedBList.add(b);
                }
            }
        }

        System.out.println("Matched List A:");
        for (A a : matchedAList) {
            System.out.println(a);
        }

        System.out.println("Matched List B:");
        for (B b : matchedBList) {
            System.out.println(b);
        }
    }
}

class A {
    private String a1;
    private int a2;

    public A(String a1, int a2) {
        this.a1 = a1;
        this.a2 = a2;
    }

    public String getA1() {
        return a1;
    }

    public int getA2() {
        return a2;
    }

    @Override
    public String toString() {
        return "A{" +
                "a1='" + a1 + '\'' +
                ", a2=" + a2 +
                '}';
    }
}

class B {
    private String b1;
    private int b2;

    public B(String b1, int b2) {
        this.b1 = b1;
        this.b2 = b2;
    }

    public String getB1() {
        return b1;
    }

    public int getB2() {
        return b2;
    }

    @Override
    public String toString() {
        return "B{" +
                "b1='" + b1 + '\'' +
                ", b2=" + b2 +
                '}';
    }
}

注：以上代码仅作为示例，实际开发中需要根据具体情况进行修改。