c# 解析json｛ "isSuccess":true, "result":true, "code":0, "errCode":0, "message":"失败错误说明", "data":null, "commit"=false ｝

以下是使用C#解析JSON的示例代码：

using System;
using Newtonsoft.Json;

public class Response
{
    public bool isSuccess { get; set; }
    public bool result { get; set; }
    public int code { get; set; }
    public int errCode { get; set; }
    public string message { get; set; }
    public object data { get; set; }
    public bool commit { get; set; }
}

public class Program
{
    public static void Main()
    {
        string json = @"{
            ""isSuccess"": true,
            ""result"": true,
            ""code"": 0,
            ""errCode"": 0,
            ""message"": ""失败错误说明"",
            ""data"": null,
            ""commit"": false
        }";

        Response response = JsonConvert.DeserializeObject<Response>(json);

        Console.WriteLine("isSuccess: " + response.isSuccess);
        Console.WriteLine("result: " + response.result);
        Console.WriteLine("code: " + response.code);
        Console.WriteLine("errCode: " + response.errCode);
        Console.WriteLine("message: " + response.message);
        Console.WriteLine("data: " + response.data);
        Console.WriteLine("commit: " + response.commit);
    }
}

这段代码使用了Newtonsoft.Json库来解析JSON字符串。首先，我们定义了一个Response类，该类的属性与JSON中的字段对应。然后，使用JsonConvert.DeserializeObject方法将JSON字符串转换为Response对象。最后，我们可以通过访问Response对象的属性来获取JSON中的值。