赛氪2024oj输入三个整数XYZ，输出整数P，P是所有小于X的数x，所有小于Y的数y，所有小于Z的数z的乘积和除998244353的余数 c语言

在C语言中，你可以使用结构化编程的方式来解决这个问题。首先，你需要让用户输入三个整数XYZ，然后计算符合条件的所有数的乘积，并对结果取模998244353。这里是一个简单的示例代码：

#include <stdio.h>

// Function to calculate product of all numbers less than a given integer modulo 998244353
unsigned long long get_product(int num) {
    unsigned long long product = 1;
    for (int i = 1; i < num; ++i) {
        product *= i;
        if (product >= 998244353) {
            product %= 998244353;
        }
    }
    return product;
}

int main() {
    int X, Y, Z;
    
    // Input three integers
    printf("Enter three integers XYZ: ");
    scanf("%d %d %d", &X, &Y, &Z);

    // Calculate the products and take mod 998244353
    unsigned long long prod_X = get_product(X - 1);
    unsigned long long prod_Y = get_product(Y - 1);
    unsigned long long prod_Z = get_product(Z - 1);

    // Calculate P as the product of these smaller products
    unsigned long long P = (prod_X * prod_Y * prod_Z) % 998244353;

    // Output the result
    printf("The value of P is: %llu\n", P);