用C语言编写一个可以无限加减乘除可以带括号的简单计算器程序

好的，我可以回答这个问题。以下是一个简单的可以无限加减乘除可以带括号的计算器程序的 C 语言代码：

#include <stdio.h>
#include <stdlib.h>

#define MAX_EXPRESSION_LENGTH 100

int evaluate_expression(char* expression);

int main() {
    char expression[MAX_EXPRESSION_LENGTH];
    printf("请输入一个数学表达式：");
    fgets(expression, MAX_EXPRESSION_LENGTH, stdin);
    int result = evaluate_expression(expression);
    printf("结果为：%d\n", result);
    return 0;
}

int evaluate_expression(char* expression) {
    int result = 0;
    int current_number = 0;
    char current_operator = '+';
    int i = 0;
    while (expression[i] != '\0') {
        if (expression[i] >= '0' && expression[i] <= '9') {
            current_number = current_number * 10 + (expression[i] - '0');
        } else if (expression[i] == '+' || expression[i] == '-' || expression[i] == '*' || expression[i] == '/') {
            if (current_operator == '+') {
                result += current_number;
            } else if (current_operator == '-') {
                result -= current_number;
            } else if (current_operator == '*') {
                result *= current_number;
            } else if (current_operator == '/') {
                result /= current_number;
            }
            current_number = 0;
            current_operator = expression[i];
        } else if (expression[i] == '(') {
            int j = i + 1;
            int parentheses_count = 1;
            while (parentheses_count > 0) {
                if (expression[j] == '(') {
                    parentheses_count++;
                } else if (expression[j] == ')') {
                    parentheses_count--;
                }
                j++;
            }
            char sub_expression[MAX_EXPRESSION_LENGTH];
            strncpy(sub_expression, expression + i + 1, j - i - 2);
            sub_expression[j - i - 2] = '\0';
            int sub_result = evaluate_expression(sub_expression);
            if (current_operator == '+') {
                result += sub_result;
            } else if (current_operator == '-') {
                result -= sub_result;
            } else if (current_operator == '*') {
                result *= sub_result;
            } else if (current_operator == '/') {
                result /= sub_result;
            }
            current_number = 0;
            i = j - 1;
        }
        i++;
    }
    if (current_operator == '+') {
        result += current_number;
    } else if (current_operator == '-') {
        result -= current_number;
    } else if (current_operator == '*') {
        result *= current_number;
    } else if (current_operator == '/') {
        result /= current_number;
    }
    return result;
}

这个程序可以读入一个数学表达式，然后计算出它的结果。它支持无限加减乘除和带括号的表达式。例如，输入 "(1+2)*3"，输出 "9"。