raise Exception("[formula] found unexpected NAME token (%r)" % name_tok.txt) AttributeError: 'CommonToken' object has no attribute 'txt'. Did you mean: 'text'?
时间: 2023-06-20 07:06:43 浏览: 88
这个错误通常会出现在使用 ANTLR 进行语法分析时,它提示解析器在处理语法时遇到了一个意外的名称标记,并且该标记似乎没有“txt”属性,但是有“text”属性。 因此,您可以尝试将代码中的“txt”更改为“text”。
例如,如果您的代码类似于以下代码:
```
if name_tok.type == FORMULA:
raise Exception("[formula] found unexpected NAME token (%r)" % name_tok.txt)
```
您可以将其更改为:
```
if name_tok.type == FORMULA:
raise Exception("[formula] found unexpected NAME token (%r)" % name_tok.text)
```
然后再次运行代码,看看问题是否已经得到解决。
相关问题
AttributeError: DataFrame object has no attribute append . Did you mean: _append ?
This error occurs when you try to call the `append` method on a Pandas DataFrame object, but the object does not have an `append` attribute.
One possible reason for this error is that you are trying to append a DataFrame to another DataFrame using the `append` method, but you are not using it correctly. In Pandas, the `append` method does not modify the original DataFrame, but instead it returns a new DataFrame that contains the rows from both DataFrames. Therefore, you need to assign the result of the `append` method to a new variable or to the original DataFrame, like this:
```
df1 = pd.DataFrame({'A': [1, 2], 'B': [3, 4]})
df2 = pd.DataFrame({'A': [5, 6], 'B': [7, 8]})
df3 = df1.append(df2)
```
In this example, `df3` will contain the rows from both `df1` and `df2`.
If you are still getting the AttributeError, it's possible that the DataFrame object you are trying to append to does not have an `append` attribute. In this case, you can try using the `_append` attribute instead, which is a private method that is used internally by Pandas. However, be aware that using private methods may not be supported in future versions of Pandas and may cause unexpected behavior.
```
df1._append(df2)
```
AttributeError: type object 'QJsonParseError' has no attribute 'NoError'. Did you mean: 'error'?
这个错误可能是因为你使用了错误的属性名称。在Python中,属性名称是区分大小写的。因此,如果你使用了大小写不正确的属性名称,它可能会引发 AttributeError。在这种情况下,QJsonParseError类没有名为NoError的属性。你可以尝试使用正确的属性名称 error 来解决这个问题。例如:
```
QJsonParseError error
if json_doc.isNull():
print("Failed to create JSON document.")
elif json_doc.isEmpty():
print("JSON document is empty.")
elif not json_doc.isObject():
print("JSON document is not an object.")
elif json_doc["key"].isNull():
print("JSON document has a null value for key 'key'.")
elif json_doc["key"].isString():
print("JSON document has a string value for key 'key':", json_doc["key"].toString())
else:
print("JSON document has an unexpected value for key 'key':", json_doc["key"].toJson())
```
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